MySQL查询与几个嵌套的JOIN

Question

我有3张桌子：

• soccer_players
• playersPoints
• soccer_fixtures

我在这里花了几个小时来构建这个查询：

SELECT * FROM `soccer_players`

INNER JOIN `playersPoints` ON `soccer_players`.player_id 
=`playersPoints`.playerID

INNER JOIN `soccer_fixtures`
    ON soccer_players.team_id = soccer_fixtures.home_team_id

WHERE soccer_fixtures.home_team_id IN (528,529,530, 531, 532, 533, 
534, 535, 536, 537, 538, 539, 540, 541, 542, 543, 544, 545)

AND soccer_fixtures.season_id = 2201
AND position != 'Coach' AND soccer_fixtures.status = "NS"
AND soccer_fixtures.game_week = 32

ORDER BY `soccer_players`.`player_name` ASC

我的结果很好，但我的问题是我想在

之后添加

INNER JOIN `soccer_fixtures`
    ON soccer_players.team_id = soccer_fixtures.home_team_id

这样：

INNER JOIN `soccer_fixtures`
    ON soccer_players.team_id = soccer_fixtures.away_team_id

我的目标是从桌子上过滤足球运动员，将他们与这些球员的分数联系起来，然后将这个结果加入到我可以显示的这个游戏周的装置中，哪个玩家正在哪个日期玩。

我知道问题是什么，但我不知道如何解决它。

不能有2个INNER JOIN具有相同的名称，但如何将这两个INNER JOIN分组为一个？

修改

我也尝试了以下内容：

SELECT * FROM `soccer_players`

INNER JOIN `playersPoints` ON `soccer_players`.player_id  
=`playersPoints`.playerID

INNER JOIN `soccer_fixtures`
    RIGHT JOIN soccer_players
    (
        ON soccer_fixtures.team_id = soccer_fixtures.home_team_id
        ON soccer_fixtures.team_id = soccer_fixtures.a_team_id
    )

WHERE

soccer_fixtures.home_team_id IN (528,529,530, 531, 532, 533, 
534, 535, 536, 537, 538, 539, 540, 541, 542, 543, 544, 545)

OR 

soccer_fixtures.a_team_id IN (528,529,530, 531, 532, 533, 
534, 535, 536, 537, 538, 539, 540, 541, 542, 543, 544, 545)

AND soccer_fixtures.season_id = 2201
AND position != 'Coach' AND soccer_fixtures.status = "NS"
AND soccer_fixtures.game_week = 32

ORDER BY `soccer_players`.`player_name` ASC

没有成功，但我认为这与解决方案很接近。

EDIT2：

好的，我现在有这个解决方案： 结果很精彩！我对这种性能感到疑惑，现在花了很长时间才得到正确的结果。我可以将查询修改为lil，以便更快地从我的3个tabkles获得结果吗？

现在是我的修改版本：

Thorsten的大事！

Answer 1

您希望在第32周选择与状态NS匹配的玩家。因此，请从玩家中进行选择。条件（与状态和周匹配）属于WHERE子句。由于玩家可以拥有多个积分，因此将每个玩家点和外部加起来加入玩家。

select sp.name, coalesce(pp.total_points, 0) as points
from soccer_players sp
left join
(
  select playerid, sum(points) as total_points
  from playerspoints 
  group by playerid
) pp on pp.playerid = sp.player_id
where exists
(
  select *
  from soccer_fixtures sf
  where sf.season_id = 2201
    and sf.game_week = 32
    and sf.status = 'NS'
    and sp.team_id in (sf.home_team_id, sf.away_team_id)
);

（不是将点子查询放在FROM子句中，您也可以在SELECT子句中使用它，但通常我们更喜欢FROM中的外连接，所以我们可以如有必要，请选择多个列。）