Question

#Guess the number game by Johnathan Millsap
import random

guessesTaken = 0

print('Hello! What is your name?')
myName = input()

number = random.randint(1, 100)
print('Well, ' + myName + ', I am thinking of a number between 1 and 100.')
print('Try to guess it!.')

while guessesTaken <= 3:
    print('Take a guess.')
    guesesTaken = guessesTaken + 1
    guess = input()
    guess = int(guess)

if guess < number:
    print('Your guess is too low.')     
if guess > number:
    print('Your guess is too high.')
if guess == number:


if guess == number:
    guesesTaken = str(guessesTaken)
    print('Good job, ' + myName + '! You guessed my number ' + guessesTaken + ' guesses!')

if guess != number:
    number = str(number)
    print('Nope. The number I was thinking of was ' + number)

我遇到的主要问题是它一直告诉我我的int不会隐含地转换成字符串...我也试图在三个不同的困难中执行此操作，如1-100和1-1000和1-10000。对此有任何帮助将不胜感激。

Traceback (most recent call last):
  File "Lab4.py", line 28, in <module>
    print('Good job, ' + myName + '! You guessed my number ' + guessesTaken + ' guesses!')
TypeError: Can't convert 'int' object to str implicitly
Terminated with exit code 1.

Answer 1

您的代码中存在打字错误

guesesTaken = str(guessesTaken)

应该是

guessesTaken = str(guessesTaken)

Answer 2

假设缩进在问题中搞砸了，并且在你的作业文件中是正确的（Lab4.py）尝试：

print('Good job, ' + myName + '! You guessed my number ' + str(guessesTaken) + ' guesses!')

Answer 3

使用str（）L

将int转换为字符串

print('Good job, ' + myName + '! You guessed my number ' + str(guessesTaken) + ' guesses!')

如何在难度为3.23的情况下制作随机数发生器

3 个答案: