Question

我正在使用GCM（Google云消息传递）向Android应用发送通知。我的服务器正在使用Google提供的gcm-server.jar，我正在关注documentation。我可以毫无问题地向设备发送通知。

现在，我正在尝试根据PushNotificationDaoGcmImpl的私有方法sendNotificationToServer返回的Result（source）对业务逻辑进行单元测试。

我知道Result不能被模拟，因为它是final类，并且只是将它实例化为new Result()将无效，因为没有公共构造函数。 Result内部Builder类在package com.google.android.gcm.server;之外无法访问，因此我无法以这种方式构建对象。

我找不到创建Result的好方法，这是从Sender（source）返回的内容。

我的问题是如何进行基于PushNotificationDaoGcmImpl Result处理某些条件的单元测试？

public class PushNotificationDaoGcmImpl{

    //method I'm trying to test
    public void sendPushNotification(){
        // builds message to send

        Result result = this.sendNotificationToServer(gcmMessage, deviceToken)

        //handle result's error conditions
    }

    //method call I'm trying to mock
    private Result sendNotificationToServer(Message gcmMessage, String deviceToken){
        return gcmSender.send(gcmMessage, deviceToken, 1);
    }
}   

//test snipet
@Test
public void testSendNotificationToServer () throws Exception {
    Result result = new Result();

    PushNotificationMessage message = new PushNotificationMessage("123", "Test", "deviceToken", "Android");

    //Having issue with how to handle Result here
    doReturn(result).when(gcmPushNotificationDaoSpy).sendNotificationToServer(any(Message.class), anyString());

    PushNotificationResult result = gcmPushNotificationDaoSpy.sendPushNotification(message);

    //verify business logic was correct based on Result
}

Answer 1

我遇到的解决方案是使用反射来创建Result对象。我不确定这是否是一种很好的方法，但我能够根据不同的Result错误代码测试业务逻辑。

@Test
public void testSendNotificationToServer () throws Exception {
    String successIndicator = null;
    Result result = buildFauxResult("messageId", "deviceToken", successIndicator);

    PushNotificationMessage message = new PushNotificationMessage("123", "Test", "deviceToken", "Android");

    //Having issue with how to handle Result here
    doReturn(result).when(gcmPushNotificationDaoSpy).sendNotificationToServer(any(Message.class), anyString());

    PushNotificationResult result = gcmPushNotificationDaoSpy.sendPushNotification(message);

    //verify business logic was correct based on Result
}

public Result buildFauxResult (String messageId, String canonicalRegistrationId, String errorCode) throws Exception {
           Class <?> builderClass = Class.forName("com.google.android.gcm.server.Result$Builder");
           Constructor <?> builderConstructor = builderClass.getDeclaredConstructors()[0];
           ReflectionUtils.makeAccessible(builderConstructor);
           Object builderObject = builderConstructor.newInstance();

           Method canonicalRegistrationIdMethod = builderClass.getMethod("canonicalRegistrationId", String.class);
           ReflectionUtils.makeAccessible(canonicalRegistrationIdMethod);
           builderObject = ReflectionUtils.invokeMethod(canonicalRegistrationIdMethod, builderObject, canonicalRegistrationId);

           Method messageIdMethod = builderClass.getMethod("messageId", String.class);
           ReflectionUtils.makeAccessible(messageIdMethod);
           builderObject = ReflectionUtils.invokeMethod(messageIdMethod, builderObject, messageId);

           Method errorCodeMethod = builderClass.getMethod("errorCode", String.class);
           ReflectionUtils.makeAccessible(errorCodeMethod);
           builderObject = ReflectionUtils.invokeMethod(errorCodeMethod, builderObject, errorCode);

           Method buildMethod = builderClass.getMethod("build");
           ReflectionUtils.makeAccessible(buildMethod);

           return (Result) ReflectionUtils.invokeMethod(buildMethod, builderObject);
    }

Answer 2

您还可以在com.google.android.gcm.server包中创建一个MockResult类，以便您访问Builder。

package com.google.android.gcm.server;

class MockResult {

    public static Result mockResult(...) {
      // Use Builder here to construct Result
    }

}

对我来说，这比处理反思更容易管理。

Java Server端UnitTesting GCM的结果

2 个答案: