$ result = mysql_query(“SELECT max(Cardex_ID)FROM cardex WHERE Onderdeel_ID = $ Onderdeel_ID”); if(!$ result){ 死('无法查询:'。mysql_error()); }
$Cardex_ID = mysql_result($result, 0, 'Cardex_ID');
echo $Cardex_ID;
mysql_query("UPDATE cardex SET PADate=$PAdate, PAhours=$PAhours, PAcycles=$PAcycles, PAlanding=$PAlanding WHERE Cardex_ID=$Cardex_ID");
答案 0 :(得分:1)
我建议您使用PDO连接到数据库而不是使用该通用连接。
此外,如果$ Onderdeel_ID是一个数字,您不应该需要""
$db = new PDO ('mysql:host=localhost;dbname=DB_NAME','DB_USER','DB_PASS');
$sql = 'SELECT max(Cardex_ID) FROM cardex WHERE Onderdeel_ID='. $Onderdeel_ID;
$result = $db->query($sql)->fetch(PDO::FETCH_ASSOC);
echo 'SELECT';
if (!$result) {
echo 'RESULT';
}
注意:同样有效且首选使用语句prepare
来阻止SQL注入:
$db = new PDO ('mysql:host=localhost;dbname=DB_NAME','DB_USER','DB_PASS');
$db->prepare ( 'SELECT max(Cardex_ID) FROM cardex WHERE Onderdeel_ID=:Onderdeel_ID');
$result = $db->execute( array( ':Onderdeel_ID' => $Onderdeel_ID ) );
此外,如果您遇到问题,请检查您的$Onderdeel_ID
是否已通过。一个简单的var_dump($Onderdeel_ID);
可以解决问题