Question

我试图找出如何在分配之前使用if语句来进行更改。这个脚本的目的是检查是否在提示之前将刀从表中取出。这样做是为了让你可以走回桌面并获得另一个回应，如果你已经采取它。我做错了什么？

def table ():
    if knife_taken == False:
        print "it's an old, brown wooden table, and atop it you find a knife"
        print "Will you take the knife or go back?"
        knife = raw_input ("> ")
        if knife.strip().lower() in ["back", "b", "no"]:
            basement2()
        elif knife.strip().lower() in ["take knife", "knife", "yes", "k"]:
            knife_taken = True
            print "You now have the knife, good, you are going to need it"
            raw_input()
            basement2()
        else:
            print "I did not understand that."
            raw_input()
            table()
    else:
        print "There's nothing on the table"
    raw_input()
    basement2()

Answer 1

基本上，当您在函数中更改变量knife_taken时，将其更改为local级别，这意味着当函数结束时，更改将丢失。有两种方法可以解决这个问题：使用global（但那是坏方法）

global knife_taken
knife_taken = True

或者你可以从函数

返回刀的状态

return knife_taken

# later on
kitchen(knife_taken)

并将其存储在变量中，稍后将其作为争论传递回厨房

或者作为额外的小奖励，您可以将游戏状态存储在字典中。然后，您可以在游戏状态发生变化时更新字典，例如。

game_state = {}

game_state['knife_taken'] = False

def kitchen():
    if not game_state['knife_taken']:
        print "Take the knife!"
        game_state['knife_taken'] = True
    else:
        print "Nothing to see here."

kitchen()
kitchen()

根据变量改变响应

1 个答案: