Question

我有一个从A点移动到随机点B的圆圈。当物体接近B点时，会选择一个新的随机目标位置。如果圆圈平行于X轴或Y轴移动，则物体会穿过所有像素并留下实线。但如果圆圈沿对角方向移动，它会跳过像素并轻微抖动，使动画不平滑并留下带有未上漆像素的痕迹。

我的算法是：

计算X和Y距离
检查圈子是否在附近
如果是，请选择新目的地
如果2.为真，请使用毕达哥拉斯＆＃39;找到真正的距离。定理
如果2.为真，则计算X和Y速度（坐标的变化）
设置新坐标（无论是否为真）

以下是代码：

  public void move ()//движение
  {
      //finds the X and Y distance to the destination
      int triangleX = nextLocationX - coorX;
      int triangleY = nextLocationY - coorY;
      //if too near the coordinates of the destination changes
      if (Math.abs(triangleX) <= Math.abs(speedX) || Math.abs(triangleY) <= Math.abs(speedY))//setting the new target
      {
          //setting the new destinatio
          int randInt;
          for (;;)//I don't want the the new destination to be that same spot
          {
              randInt= randGen.nextInt(appletX);
              if (randInt != nextLocationX)
              {
                  nextLocationX = randInt + radius;
                  break;
              }
          }
          for (;;)
          {
              randInt = randGen.nextInt(appletY);
              if (randInt != nextLocationY)
              {
                  nextLocationY = randInt + radius;
                  break;
              }
          }
          //calculating the change of the circle's X and Y coordinates
          triangleX = nextLocationX - coorX;
          triangleY = nextLocationY - coorY;
          speedX = ((double)(speed * triangleX) / (Math.sqrt (Math.pow(triangleX, 2) + Math.pow(triangleY, 2))));
          speedY = ((double)(speed * triangleY) / (Math.sqrt (Math.pow(triangleX, 2) + Math.pow(triangleY, 2))));
      }
      //the realCoor variables are from type double
      //they are the exact coordinates of the circle
      //If I only use integers, the circle almost
      //never reaches it's destination
      //unless the change of the coordinates gets calculated
      //after every time they change
      realCoorX = realCoorX + speedX;
      realCoorY = realCoorY + speedY;
      coorX = (int)Math.round(realCoorX);
      coorY = (int)Math.round(realCoorY);
  }

我怀疑问题在于计算坐标的变化。

Answer 1

对我而言，这听起来像是一个别名问题。如果绘制（！）与坐标轴不对齐的线，则会出现同样的问题。如您所知，即对角线需要“半满”像素才能看起来光滑。

您将使用浮点位置计算（取决于渲染技术）。

Java：在路径上移动的对象，忽略某些坐标。怎么修？

1 个答案: