Question

所以我试图使用std :: chrono :: high_resolution_clock来计算执行时间需要多长时间。我想你可以找到开始时间和结束时间之间的差异......

为了检查我的方法，我做了以下程序：

#include <iostream>
#include <chrono>
#include <vector>

void long_function();

int main()
{
    std::chrono::high_resolution_clock timer;
    auto start_time = timer.now();

    long_function();

    auto end_time = timer.now();
    auto diff_millis = std::chrono::duration_cast<std::chrono::duration<int, std::milli>>(end_time - start_time);

    std::cout << "It took " << diff_millis.count() << "ms" << std::endl;
    return 0;
}

void long_function()
{
    //Should take a while to execute.
    //This is calculating the first 100 million
    //fib numbers and storing them in a vector.
    //Well, it doesn't actually, because it
    //overflows very quickly, but the point is it
    //should take a few seconds to execute.
    std::vector<unsigned long> numbers;
    numbers.push_back(1);
    numbers.push_back(1);
    for(int i = 2; i < 100000000; i++)
    {
        numbers.push_back(numbers[i-2] + numbers[i-1]);
    }
}

问题是，它实际上只输出了3000毫秒，而实际上并非如此。

在较短的问题上，它只输出0ms ......我做错了什么？

编辑：如果它有用，我正在使用带有-std = c ++ 0x标志的GNU GCC编译器

Answer 1

high_resolution_clock的分辨率取决于平台。

打印以下内容可以让您了解所使用的实施的解决方案

    std::cout << "It took " << std::chrono::nanoseconds(end_time - start_time).count() << std::endl;

Answer 2

我在window7下遇到了与g ++（rev5，由MinGW-W64项目建立）4.8.1类似的问题。

int main()
{
    auto start_time = std::chrono::high_resolution_clock::now();
    int temp(1);
    const int n(1e7);
    for (int i = 0; i < n; i++)
        temp += temp;
    auto end_time = std::chrono::high_resolution_clock::now();
    std::cout << std::chrono::duration_cast<std::chrono::nanoseconds>(end_time - start_time).count() << " ns.";
    return 0;
}

如果n = 1e7，则显示19999800 ns 但如果 n = 1e6，显示0 ns。

精度似乎很弱。

std :: chrono :: high_resolution_clock不准确？

2 个答案: