看起来很简单,但我认为我的程序无法编译,因为我正在覆盖$ v0寄存器?提前致谢
更新:没关系得到它,当我打印系统来打印总和时,我的订单错了... 修复以防任何人需要参考。
.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"
.text
main:
#t0-to hold first integer
#t1-to hold second integer
#t2- used to hold the sum of t$1 and t$2
#first number
li $v0, 4 #syscall to print string
la $a0, prompt1 #address of string to print
syscall
li $v0, 5 #syscall to read an integer
syscall
move $t0, $v0 #move the number to read into $t0
#second number
li $v0, 4
la $a0, prompt2
syscall
li $v0,5
syscall
move $t1,$v0
add $t2, $t1, $t0 #compute the sum
#print out sum of $t2
li $v0, 4 # load syscall print int into $v0
move $a0, $t2 #move the number to print into $a0
li, $v0,1
la, $a0, result
syscall
Done:
li $v0, 10 #syscall to exit
syscall
答案 0 :(得分:5)
.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"
.text
main:
#t0-to hold first integer
#t1-to hold second integer
#t2- used to hold the sum of t$1 and t$2
#first number
li $v0, 4 #syscall to print string
la $a0, prompt1 #address of string to print
syscall
#
li $v0, 5 #syscall to read an integer
syscall
move $t0, $v0 #move the number to read into $t0
#second number
li $v0, 4
la $a0, prompt2
syscall
#
li $v0,5
syscall
move $t1,$v0
#
#print out sum of $t2
li $v0, 4
la $a0, result
syscall
#
add $a0, $t1, $t0 #compute the sum
li $v0, 1
syscall
#
li $v0, 10
syscall
答案 1 :(得分:0)
实际上你在这部分搞砸了:
#print out sum of $t2
li $v0, 4 # load syscall print int into $v0
move $a0, $t2 #move the number to print into $a0
li, $v0,1
la, $a0, result
syscall
让我们一行一行:
li $v0, 4 #You are ready to indicate that you want to print string
la $a0, result #you have loaded the address of string now
syscall # Now you will see: "The result is:
现在让我们打印数字
li $v0, 1
move $a0, $t2
syscall
脚注:每当您指示您将使用系统调用时,您应该首先完成该命令。 例如,如果要打印某些内容,则必须完成该集的系统调用,然后继续打印整数。
例如: 让我们说我们想要打印这样的东西。 数量:1
MIPS代码将是:
.data
prompt: .asciiz "Number : "
.text
main:
#Now lets read a number
li $v0, 5
syscall # -> note syscall is done for each instruction
#Lets complete printing first
li $v0, 4
la $a0, prompt
syscall
#我们现在有$ t0的数字
#if我们这样做
li $v0, 1
la $a0, prompt
syscall
#ask问答自己。什么将被打印。
#the我们输入的数字或提示的地址
#你需要在这里修改什么?
答案 2 :(得分:0)
.text
main:
#print the msg1
li $v0 4
la $a0 msg1
syscall
#read the num 1
li $v0 5
syscall
sw $v0 a1
#print the msg2
li $v0 4
la $a0 msg2
syscall
#read the Num 2
li $v0 5
syscall
sw $v0 a2
#print the msg3
li $v0 4
la $a0 msg3
syscall
lw $t0 a1
lw $t1 a2
li $v0 1
add $a0 $t0 $t1
syscall
.data
msg1: .asciiz "Enter the first number :"
msg2: .asciiz "Enter the second number :"
a1 : .word 0
a2 : .word 0
msg3: .asciiz "The sum is = "