启动Celery:AttributeError:'module'对象没有属性'celery'

时间:2012-11-25 20:52:25

标签: python django celery django-celery

我尝试从命令行启动Celery worker服务器:

celery -A tasks worker --loglevel=info

tasks.py中的代码:

import os
os.environ[ 'DJANGO_SETTINGS_MODULE' ] = "proj.settings"

from celery import task

@task()
def add_photos_task( lad_id ):
...

我收到了下一个错误:

Traceback (most recent call last):
  File "/usr/local/bin/celery", line 8, in <module>
    load_entry_point('celery==3.0.12', 'console_scripts', 'celery')()
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/__main__.py", line 14, in main
    main()
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/bin/celery.py", line 946, in main
    cmd.execute_from_commandline(argv)
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/bin/celery.py", line 890, in execute_from_commandline
    super(CeleryCommand, self).execute_from_commandline(argv)))
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/bin/base.py", line 177, in execute_from_commandline
    argv = self.setup_app_from_commandline(argv)
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/bin/base.py", line 295, in setup_app_from_commandline
    self.app = self.find_app(app)
  File "/usr/local/lib/python2.7/site-packages/celery-3.0.12-py2.7.egg/celery/bin/base.py", line 313, in find_app
    return sym.celery
AttributeError: 'module' object has no attribute 'celery'

有人知道为什么找不到'芹菜'属性吗?谢谢你的帮助。

操作系统是Linux Debian 5.

修改即可。可能是线索。任何人都可以向我解释函数的下一个注释(为什么我们必须确保它在当前目录中找到模块)?

# from celery/utils/imports.py
def import_from_cwd(module, imp=None, package=None):
    """Import module, but make sure it finds modules
    located in the current directory.

    Modules located in the current directory has
    precedence over modules located in `sys.path`.
    """
    if imp is None:
        imp = importlib.import_module
    with cwd_in_path():
        return imp(module, package=package)

6 个答案:

答案 0 :(得分:21)

我忘了在tasks.py中创建一个芹菜对象:

from celery import Celery
from celery import task  

celery = Celery('tasks', broker='amqp://guest@localhost//') #!

import os

os.environ[ 'DJANGO_SETTINGS_MODULE' ] = "proj.settings"

@task()
def add_photos_task( lad_id ):
...

之后我们可以正常启动任务:

celery -A tasks worker --loglevel=info

答案 1 :(得分:9)

Celery使用celery文件存储应用程序的配置,你不能只给python文件包含任务并启动芹菜。 您应该定义celery文件(对于Celery&gt; 3.0;以前它是celeryconfig.py)..

  

celeryd --app app.celery -l info

此示例如何使用app/celery.py

中的配置文件启动celery

以下是芹菜文件的示例:https://github.com/Kami/libcloud-sandbox/blob/master/celeryconfig.py

答案 2 :(得分:5)

对于因明显不同原因而收到相同错误消息的任何人,请注意,如果初始化文件中的任何导入失败,您的应用程序将提升这个完全不明确的AttributeError而不是最初导致的异常它

答案 3 :(得分:2)

运行celery -A tasks worker --loglevel=info时,您的celery应用应在模块tasks中公开。不应将其包装在函数或if语句中。

如果您make_celery在另一个文件中,则应将celery应用程序导入要传递给celery的文件中。

答案 4 :(得分:1)

尝试开始芹菜:

celeryd --config=my_app.my_config --loglevel=INFO --purge -Q my_queue

我的tasks.py中有下一个脚本:

@task(name="my_queue", routing_key="my_queue")
def add_photos_task( lad_id ):

my_config.py中有下一个脚本:

CELERY_IMPORTS = \
(
    "my_app.tasks",
)
CELERY_ROUTES = \
{
    "my_queue":
    {
        "queue": "my_queue"
    },
}
CELERY_QUEUES = \
{
    "my_queue":
    {
        "exchange": "my_app",
        "exchange_type": "direct",
        "binding_key": "my_queue"
    },
}
celery = Celery(broker='amqp://guest@localhost//')

答案 5 :(得分:1)

我的问题是我将celery变量放在了一个主要函数中:

if __name__ == '__main__':  # Remove this row
    app = Flask(__name__)
    celery = make_celery(app) 

什么时候应该放在外面。