Question

晚上好

我在这里有一个问题。我有两个数组：$ duration_c [$ k] [$ s]。它打印所有确定

$duration_c[0][0]="19:30:00";
$duration_c[0][1]="00:10:00";

$duration_c[1][0]="00:30:00";
$duration_c[1][1]="00:20:00";

而不是总和

$times=$duration_c[$k][$s];
function sum_the_time($times) {

  $seconds = 0;
  foreach ($times as $time)
  {
    list($hour,$minute,$second) = explode(':', $time);
    $seconds += $hour*3600;
    $seconds += $minute*60;
    $seconds += $second;
 }
  $hours = floor($seconds/3600);
  $seconds -= $hours*3600;
  $minutes  = floor($seconds/60);
  $seconds -= $minutes*60;
  // return "{$hours}:{$minutes}:{$seconds}";
  return sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);
} 
echo sum_the_time($times);

如何总结$ duration_c [0] [0] + $ duration_c [0] [1]和$ duration_c [1] [0] + $ duration_c [1] [1]，以及如何打印？有错误为foreach（）提供的参数无效

Answer 1

您只向sum_the_time函数发送一个值为$times=$duration_c[$k][$s]; $ times只有一个值可以打印，并通过这样写

来检查函数的值

$times=$duration_c[$k][$s];
echo $times;

使用

$times=$duration_c[$k];

这样您就可以将数组发送到您的函数，而foreach不会给您错误

$times=$duration_c[$k]; // contains array of times
function sum_the_time($times) {

  $seconds = 0;
  foreach ($times as $time)
  {
    list($hour,$minute,$second) = explode(':', $time);
    $seconds += $hour*3600;
    $seconds += $minute*60;
    $seconds += $second;
 }
  $hours = floor($seconds/3600);
  $seconds -= $hours*3600;
  $minutes  = floor($seconds/60);
  $seconds -= $minutes*60;
  // return "{$hours}:{$minutes}:{$seconds}";
  return sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);
} 
echo sum_the_time($times);

Answer 2

这在PHP代码中的作用较小，并且在PHP运行时中尽可能多地保持执行流程，用C语言编写：

<?php
$duration_c[0][0]="19:30:00";
$duration_c[0][1]="00:10:00";

$duration_c[1][0]="00:30:00";
$duration_c[1][1]="00:20:00";

$sum = 0;
foreach($duration_c as $durations) {
    $today = strtotime('today');
    $sum += array_sum(array_map(function($str) use ($today) {
        return strtotime($str)-$today;
    }, $durations));
}
echo $sum; // 73800 seconds, that's 20.5 hours

Answer 3

$times=$duration_c[$k][$s];应为$times=$duration_c[$k];，否则您只会传递一次该函数，而不是一次数。

如何求和2d数组

3 个答案: