2D阵列的总和

时间:2018-08-14 13:20:40

标签: ipython jupyter-notebook

具有以下一维数组时

   u = (integerTextureCoord + .5) / width

我可以通过以下方式获得数组的总和:

A = [ 0.01714783  0.04661262  0.93623955]
shape A = (3,)

总和为print("Sum A classes = " +str(np.sum(A, axis=0)))

我想知道我现在何时拥有2D阵列

Sum A classes = 1.0

形状A =(3,3)

如何取总和,所以我得到了:

A =  [[0.0171483 0.04661262 0.93623955]
     [0.0171483 0.04661262 0.93623955]
     [0.0171483 0.04661262 0.93623955]]

0 个答案:

没有答案