Question

我正在使用JPA来管理我的持久层。我的一个Criteria API会引发异常。我在JPQL中重新编写它并且它工作得很好所以我想我错过了我的标准api版本的东西。这是我的标准api查询：

public FoodItemTagsOverrideRule findByFoodItemIdAndType(long foodItemId, RuleTypes ruleType) {
 CriteriaQuery<Rule> c = getCriteriaQuery();
 Root<Rule> rule =
 c.from(Rule.class);
 Predicate foodItemIdCondition =
 cb.equal(rule.get(Rule_.foodItemId), foodItemId);
 Predicate typeCondition =
 cb.equal(rule.get(Rule_.ruleType),
 ruleType.toString());
 c.where(foodItemIdCondition, typeCondition);

 TypedQuery<Rule> q =
 entityManager.createQuery(c);
 List<Rule> result = q.getResultList();
 if (result.isEmpty()) {
 return null;
 }
 return result.get(0);
}

运行得很好的JPQL版本：

public Rule findByFoodItemIdAndType(long foodItemId, RuleTypes ruleType) {
    TypedQuery<Rule> query = getEntityManager().createQuery(
        "SELECT rule " + "FROM " + Rule.class.getSimpleName() + " rule " + "WHERE rule.foodItemId = :foodItemId "
        + "AND rule.ruleType = :ruleType", Rule.class);

query.setParameter("foodItemId", foodItemId);
query.setParameter("ruleType", ruleType.toString());

List<Rule> result = query.getResultList();

if (result.isEmpty()) {
    return null;
}
return result.get(0);
}

你能看到有什么区别吗？我是否在标准api查询中出错？

Thakns！

Answer 1

您可以尝试以下代码。我试图适应你的代码，你可以相应地改变。

CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery cq = qb.createQuery();
Root<Rule> rule = cq.from(Rule.class);

List<Predicate> predicates = new ArrayList<Predicate>();

predicates.add(qb.equal(rule.get("foodItemId"), foodItemId));
predicates.add(qb.equal(rule.get("ruleType"), ruleType));

cq.select(rule).where(predicates.toArray(new Predicate[]{}));
em.createQuery(cq).getResultList();

编辑：对于类型安全的谓词定义

predicates.add(qb.equal(rule.get(Rule_.foodItemId), foodItemId));
predicates.add(qb.equal(rule.get(Rule_.ruleType), ruleType));

当JPQL通过时，JPA Criteria api查询失败

1 个答案: