Question

我正在尝试制作win32应用程序，我模拟我按下钢琴上的C键，键盘No 60，然后拨打以下电话：midiOutShortMsg (hMidiOut, DWORD (0x090 | 0 | (60 << 8) | (64 << 16)));

当释放密钥no 60时，请执行以下呼叫：midiOutShortMsg (hMidiOut, DWORD (0x080 | 0 | (60 << 8) | (0 << 16)));

问题是当我按下按钮时，我只听到一次声音。当我运行程序时，只有一个案例有效。

只要按下，我该怎么做才能重复声音。如何制作长长的旋律。

case WM_KEYDOWN:
{
    switch (wParam) {

    case VK_LEFT:
        midiOutOpen(&hMidiOut, -1, 0, 0, 0);
        // Set instrument to 0 = Acoustic Grand Piano
        midiOutShortMsg(hMidiOut, DWORD(0x0C0 | 0 | (0 << 8) | (0 << 16)));
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (65<<8 ) | (64 << 16)));
        break;

    case 'S':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (62<<8 ) | (64 << 16)));   
        break;

    case 'D':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (64<<8 ) | (64 << 16)));
        break;

    case 'F':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (65<<8 ) | (64 << 16)));
        break;

    case 'G':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (67<<8 ) | (64 << 16)));
        break;

    case 'H':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (69<<8 ) | (64 << 16)));
        break;

    case 'J':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (71<<8 ) | (64 << 16)));
        break;

    case 'K':
        midiOutShortMsg (hMidiOut, DWORD(0x090 | 0 | (72<<8 ) | (64 << 16)));
        break;

Answer 1

我猜你可以存储键状态（可能使用bool数组）并在消息处理循环中进行播放。

C ++ Win32-响应按键

1 个答案: