使用getUserMedia我可以从客户端的网络摄像头/摄像头捕获视频流。使用video
标记我可以在客户端的浏览器上显示它。代码:
<video autoplay></video>
<script type="text/javascript">
window.URL = window.URL || window.webkitURL;
navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia;
var video = $('video')[0];
var failed = function(e) {
console.log('Denied!', e);
};
if( navigator.getUserMedia ) {
navigator.getUserMedia( {video: true, audio: true}, function( stream ) {
video.src = window.URL.createObjectURL(stream);
}, failed
)
} else {
console.log( 'Not supported!' );
}
</script>
现在是否可以将此视频流作为实时Feed或用户完成录制并决定上传到服务器后发送?
我找到了几个例子:
答案 0 :(得分:12)
MediaStreamRecorder是一个用于记录getUserMedia()流的WebRTC API。它允许Web应用程序通过实时音频/视频会话创建文件。
<video autoplay></video>
<script language="javascript" type="text/javascript">
function onVideoFail(e) {
console.log('webcam fail!', e);
};
function hasGetUserMedia() {
// Note: Opera is unprefixed.
return !!(navigator.getUserMedia || navigator.webkitGetUserMedia ||
navigator.mozGetUserMedia || navigator.msGetUserMedia);
}
if (hasGetUserMedia()) {
// Good to go!
} else {
alert('getUserMedia() is not supported in your browser');
}
window.URL = window.URL || window.webkitURL;
navigator.getUserMedia = navigator.getUserMedia ||
navigator.webkitGetUserMedia ||
navigator.mozGetUserMedia ||
navigator.msGetUserMedia;
var video = document.querySelector('video');
var streamRecorder;
var webcamstream;
if (navigator.getUserMedia) {
navigator.getUserMedia({audio: true, video: true}, function(stream) {
video.src = window.URL.createObjectURL(stream);
webcamstream = stream;
// streamrecorder = webcamstream.record();
}, onVideoFail);
} else {
alert ('failed');
}
function startRecording() {
streamRecorder = webcamstream.record();
setTimeout(stopRecording, 10000);
}
function stopRecording() {
streamRecorder.getRecordedData(postVideoToServer);
}
function postVideoToServer(videoblob) {
var data = {};
data.video = videoblob;
data.metadata = 'test metadata';
data.action = "upload_video";
jQuery.post("http://www.kongraju.in/uploadvideo.php", data, onUploadSuccess);
}
function onUploadSuccess() {
alert ('video uploaded');
}
</script>
<div id="webcamcontrols">
<button class="recordbutton" onclick="startRecording();">RECORD</button>
</div>
<强>规格:强>
http://www.w3.org/TR/mediastream-recording/
您可以将录制的文件发送到服务器。
答案 1 :(得分:3)
它显示了Webrtc的使用:
这些API应该能够构建可以在浏览器中运行的应用程序,无需额外的下载或插件,允许使用音频,视频和补充实时通信的各方之间的通信,而无需使用中间服务器(除非需要防火墙遍历,或提供中介服务)。