Question

我必须执行SQL查询才能根据视图数量获得前10个专辑。视图数实际上是指定相册中每首歌曲的视图总和。

我的表是：

albums:
- album_id
- album_name
- album_owner

songs:
- song_id
- song_name
- song_album
- song_owner
- song_views

你能帮我解决这个问题吗？

Answer 1

select sum(song_views) as 'song_sum',album_name 
from albums a 
inner join 
songs s 
on a.album_id = s.song_album 
group by album_name 
order by song_sum DESC 
limit 0,10;

如果song_album指的是专辑ID ...

Answer 2

试试这个：

SELECT  TOP 10 a.album_id, a.album_name, a.album_owner, SUM(s.song_views)
FROM    albums a
        INNER JOIN
                songs s
                ON a.album_id = s.song_album
GROUP BY a.album_id, a.album_name, a.album_owner
ORDER BY SUM(s.song_views) DESC

Answer 3

类似的东西：

select top 10 song_album
from songs
group by song_album
order by sum(song_views) desc

Answer 4

我无法运行，但它应该是

select album_name, sum(song_views) as views from albums join songs on songs.album_id = songs.song_album group by album_id order by views desc limit 10

Answer 5

SELECT TOP 10 song_album FROM songs GROUP BY song_album ORDER BY sum（song_views）desc

帮助SQL查询

5 个答案: