我对SQL查询有疑问,我想知道从哪里开始。到目前为止的想法包括在记忆中创建一个包含一系列日期的表格,并加入其中以获得特定日期输入的小时数。
这里只是为了解一下这个问题的背景知识。
数据库的结构如下:
尝试使用当前正在编写的查询实现的结果需要如下所示:
到目前为止我写的查询:
DECLARE @Deleted AS BIT
DECLARE @WeekStartDate AS DATETIME
DECLARE @WeekEndDate AS DATETIME
SET @Deleted = 0
SET @WeekStartDate = '2011/05/01 00:00'
SET @WeekEndDate = '2011/05/07 00:00'
SELECT
[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
SUM([JobSheetLineHours].[Hours]) AS TotalCostRateHours,
'???' AS 'Mon',
'???' AS 'Tue',
'???' AS 'Wed',
'???' AS 'Thu',
'???' AS 'Fri',
'???' AS 'Sat',
'???' AS 'Sun'
FROM [JobSheet]
INNER JOIN [JobSheetLine]
ON [JobSheetLine].[JobSheetID]
= [JobSheet].[JobSheetID]
INNER JOIN [JobSheetLineHours]
ON [JobSheetLineHours].[JobSheetLineID]
= [JobSheetLine].[JobSheetLineID]
WHERE
[JobSheet].[Deleted]=@Deleted
AND [JobSheet].[JobSheetDate] >= @WeekStartDate
AND [JobSheet].[JobSheetDate] <= @WeekEndDate
AND [JobSheetLine].[Deleted]=@Deleted
AND [JobSheetLineHours].[Deleted]=@Deleted
GROUP BY
[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode]
然后输出以下结果集:
正如您所看到的那样,结果集几乎就在那里,我只需要计算该特定日期的工作小时数,对ContractID,JobID,ProjectID,CostRateCode进行分组,这样我就可以获得每个成本费率的小时数在每个独特的项目上。
目前的表格设计是否可以实现?或者通过使用临时日历表来确定传递给查询的两者之间的日期?
编辑: 更新的查询:
SET DATEFIRST 1 -- Set the first day of week to monday
GO
DECLARE @Deleted AS BIT
DECLARE @RequestedByID AS BIGINT
DECLARE @WeekStartDate AS DATETIME
DECLARE @WeekEndDate AS DATETIME
DECLARE @WaitingForUserID AS BIGINT
DECLARE @WaitingForUserTypeID AS BIGINT
DECLARE @WaitingForTypeUser AS VARCHAR(50)
DECLARE @WaitingForTypeUserType AS VARCHAR(50)
SET @Deleted = 0
SET @WeekStartDate = '2009/05/01 00:00'
SET @WeekEndDate = '2012/05/07 00:00'
SELECT
[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
SUM([JobSheetLineHours].[Hours]) AS TotalCostRateHours,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 1
THEN SUM(JobSheetLineHours.Hours )
END
AS MON,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 2
THEN SUM(JobSheetLineHours.Hours )
END
AS TUE,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 3
THEN SUM(JobSheetLineHours.Hours )
END
AS WED,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 4
THEN SUM(JobSheetLineHours.Hours )
END
AS THU,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 5
THEN SUM(JobSheetLineHours.Hours )
END
AS FRI,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 6
THEN SUM(JobSheetLineHours.Hours )
END
AS SAT,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 7
THEN SUM(JobSheetLineHours.Hours )
END
AS SUN
FROM [JobSheet]
INNER JOIN [JobSheetLine]
ON [JobSheetLine].[JobSheetID]
= [JobSheet].[JobSheetID]
INNER JOIN [JobSheetLineHours]
ON [JobSheetLineHours].[JobSheetLineID]
= [JobSheetLine].[JobSheetLineID]
WHERE
[JobSheet].[Deleted]=@Deleted
AND [JobSheet].[JobSheetDate] >= @WeekStartDate
AND [JobSheet].[JobSheetDate] <= @WeekEndDate
AND [JobSheetLine].[Deleted]=@Deleted
AND [JobSheetLineHours].[Deleted]=@Deleted
GROUP BY
[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 1
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 2
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 3
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 4
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 5
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 6
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 7
THEN JobSheetLineHours.Hours
END
更新的结果集:
我现在要做的是从结果集中删除JobSheetDate,以便每天的总小时数不是全部在单独的行上,例如。同一合同,项目等的值放在同一行,但是在Mon,Tues,Wed等列中,而不是在多行中填充一天的小时数,其余时间为null(参见屏幕截图) )
编辑2: 更新的查询:
SET DATEFIRST 1 -- Set the first day of week to monday
GO
DECLARE @Deleted AS BIT
DECLARE @WeekStartDate AS DATETIME
DECLARE @WeekEndDate AS DATETIME
SET @Deleted = 0
SET @WeekStartDate = '2009/05/01 00:00'
SET @WeekEndDate = '2012/05/07 00:00'
SELECT
--[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
SUM([JobSheetLineHours].[Hours]) AS TotalCostRateHours,
SUM( CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 1
THEN JobSheetLineHours.Hours
END )
AS MON,
SUM( CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 2
THEN JobSheetLineHours.Hours
END )
AS TUE,
SUM(CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 3
THEN JobSheetLineHours.Hours
END)
AS WED,
SUM( CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 4
THEN JobSheetLineHours.Hours
END)
AS THU,
SUM(CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 5
THEN JobSheetLineHours.Hours
END )
AS FRI,
SUM( CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 6
THEN JobSheetLineHours.Hours
END )
AS SAT,
SUM( CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 7
THEN JobSheetLineHours.Hours
END )
AS SUN
FROM [JobSheet]
INNER JOIN [JobSheetLine]
ON [JobSheetLine].[JobSheetID]
= [JobSheet].[JobSheetID]
INNER JOIN [JobSheetLineHours]
ON [JobSheetLineHours].[JobSheetLineID]
= [JobSheetLine].[JobSheetLineID]
WHERE
[JobSheet].[Deleted]=@Deleted
AND [JobSheet].[JobSheetDate] >= @WeekStartDate
AND [JobSheet].[JobSheetDate] <= @WeekEndDate
AND [JobSheetLine].[Deleted]=@Deleted
AND [JobSheetLineHours].[Deleted]=@Deleted
GROUP BY
--[JobSheet].[JobSheetDate],
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate)
WHEN 1
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 2
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 3
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 4
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 5
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 6
THEN JobSheetLineHours.Hours
END,
CASE DATEPART(WEEKDAY, JobSheet.JobSheetDate) WHEN 7
THEN JobSheetLineHours.Hours
END
结果:
完成查询的最终更新:
SET DATEFIRST 1 -- Set the first day of week to monday
GO
DECLARE @Deleted AS BIT
DECLARE @WeekStartDate AS DATETIME
DECLARE @WeekEndDate AS DATETIME
SET @Deleted = 0
SET @WeekStartDate = '2009/05/01 00:00'
SET @WeekEndDate = '2012/05/07 00:00'
SELECT
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode],
SUM([JobSheetLineHours].[Hours]) AS TotalCostRateHours,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Monday
WHEN 1
THEN [JobSheetLineHours].[Hours]
END )
AS MON,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Tuesday
WHEN 2
THEN [JobSheetLineHours].[Hours]
END )
AS TUE,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Wednesday
WHEN 3
THEN [JobSheetLineHours].[Hours]
END )
AS WED,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Thursday
WHEN 4
THEN [JobSheetLineHours].[Hours]
END )
AS THU,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Friday
WHEN 5
THEN [JobSheetLineHours].[Hours]
END )
AS FRI,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Saturday
WHEN 6
THEN [JobSheetLineHours].[Hours]
END )
AS SAT,
SUM( CASE DATEPART(WEEKDAY, [JobSheet].[JobSheetDate]) -- Get Total Value for Sunday
WHEN 7
THEN [JobSheetLineHours].[Hours]
END )
AS SUN
FROM [JobSheet]
INNER JOIN [JobSheetLine]
ON [JobSheetLine].[JobSheetID]
= [JobSheet].[JobSheetID]
INNER JOIN [JobSheetLineHours]
ON [JobSheetLineHours].[JobSheetLineID]
= [JobSheetLine].[JobSheetLineID]
WHERE
[JobSheet].[Deleted]=@Deleted
AND [JobSheet].[JobSheetDate] >= @WeekStartDate
AND [JobSheet].[JobSheetDate] <= @WeekEndDate
AND [JobSheetLine].[Deleted]=@Deleted
AND [JobSheetLineHours].[Deleted]=@Deleted
GROUP BY
[JobSheet].[ContractID],
[JobSheet].[ContractCode],
[JobSheet].[ContractTitle],
[JobSheet].[ProjectID],
[JobSheet].[ProjectCode],
[JobSheet].[ProjectTitle],
[JobSheet].[JobID],
[JobSheet].[JobCode],
[JobSheet].[JobTitle],
[JobSheet].[SageDatabaseID],
[JobSheetLineHours].[CostRateCode]
答案 0 :(得分:7)
如果我理解正确,您需要将其添加到SELECT
编辑由于你需要总和,你需要围绕案例添加和解
SUM(CASE WHEN DATEPART(WEEKDAY, JobSheet.JobSheetDate) = 1 THEN
JobSheetLineHours.Hours
END) AS MON,
SUM(CASE WHEN DATEPART(WEEKDAY, JobSheet.JobSheetDate) = 2 THEN
JobSheetLineHours.Hours
END) AS TUE,
SUM(CASE WHEN DATEPART(WEEKDAY, JobSheet.JobSheetDate) = 3 THEN
JobSheetLineHours.Hours
END) AS WED,
SUM(CASE WHEN DATEPART(WEEKDAY, JobSheet.JobSheetDate) = 4 THEN
JobSheetLineHours.Hours
END) AS THU,
SUM(CASE WHEN DATEPART(WEEKDAY, JobSheet.JobSheetDate) = 5 THEN
JobSheetLineHours.Hours
END) AS FRI,
您还需要从SELECT
和GROUP BY
删除任何[JobSheet]。[JobSheetDate],以便在一行中获取所有日期
如评论中所述,这取决于SET DATEFIRST的设置方式
还应该注意的是,只要你有SUM(CASE
,肯定有PIVOT
替代
答案 1 :(得分:4)
创建具体的日历表是完全可以接受的(并且通常是最佳的)。
桌子小而轻,您可以JOIN
轻松地按照您想要的任何日期组合分组。如果您愿意,也可以添加一列来表示工作日和非工作日。
否则获得“零小时”日是很尴尬的,因为你要求从不存在的数据进行聚合。
答案 2 :(得分:2)
我使用示例表方案调查它。希望它会对你有所帮助。从未经历过这种情况。很高兴今天学到新东西。感谢帖子 WraithNath
create table #temp
(
projectId int,
ContractID int,
CostRateCode varchar(10),
JobSheetDate datetime,
Hours Int
)
我插入了以下几条记录
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 1, 'A', '2011-06-02 22:00:35.337', 1)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 1, 'A', '2011-06-01 22:00:35.337', 2)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 1, 'A', '2011-05-31 22:00:35.337', 3)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 1, 'A', '2011-06-03 22:00:35.337', 6)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 1, 'A', '2011-05-30 22:00:35.337', 5)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 2, 'B', '2011-05-31 22:00:35.337', 4)
Insert into #temp(projectId, ContractID, CostRateCode, JobSheetDate, Hours)
Values(1, 2, 'B', '2011-06-01 22:00:35.337', 7)
以下是插入后的情况
最后是select语句
SET DATEFIRST 1
Select projectId ,ContractID ,CostRateCode,Sum(Hours) Total,
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 1 Then Hours Else 0 End) as 'Mon',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 2 Then Hours Else 0 End) as 'Tue',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 3 Then Hours Else 0 End) as 'Wed',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 4 Then Hours Else 0 End) as 'Thu',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 5 Then Hours Else 0 End) as 'Fri',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 6 Then Hours Else 0 End) as 'Sat',
SUM(Case When DATEPART(WEEKDAY, JobSheetDate) = 7 Then Hours Else 0 End) as 'Sun'
From #temp
Group By projectId ,ContractID ,CostRateCode
Drop table #temp
结果集
答案 3 :(得分:0)
尝试使用子查询,其中包含日期的问号,一周中每天的一个子查询;当天的日期是根据传入的日期计算的。星期一的日期是:
( SELECT SUM([JobSheetLineHours].[Hours])
FROM [JobSheet]
INNER JOIN [JobSheetLine] ON [JobSheetLine].[JobSheetID] =
[JobSheet].[JobSheetID]
INNER JOIN [JobSheetLineHours] ON [JobSheetLineHours].[JobSheetLineID] =
[JobSheetLine].[JobSheetLineID]
WHERE[JobSheet].[JobSheetDate] = @WeekStartDate + 1 AND
[JobSheet].[Deleted]=@Deleted AND
[JobSheetLine].[Deleted]=@Deleted AND
[JobSheetLineHours].[Deleted]=@Deleted )
星期二你会加2等等。
注意:这只有在@WeekStartDate确实是星期天的情况下才有效,尽管你似乎已经假设了这样。