获取字典的长度

Question

嘿，我在VB.net的这个Dictionary类中是新手。

我想重新检索Dictionary数组中有多少项：

但是这样做：

Dim showNumber As Integer = tmpShows.Length

似乎不应该产生 4 吗？

我所拥有的词典的代码是：

Dim all = New Dictionary(Of String, Object)()
Dim info = New Dictionary(Of String, Object)()

info!Station = .SelectSingleNode(".//span[@class='channel']").ChildNodes(3).ChildNodes(2).InnerText
info!Shows = From tag In .SelectNodes(".//a[@class='thickbox']")
             Select New With {.Show = tag.Attributes("title").Value, .Link = tag.Attributes("href").Value}

Dim tmpShows = all.Item(info!Station)
Dim showNumber As Integer = tmpShows.Length

为了获得 4 长度，我缺少什么？

更新

    Dim all = New Dictionary(Of String, Object)()

    For Each channel In doc.DocumentNode.SelectNodes(".//div[@class='channel_row']")
        Dim info = New Dictionary(Of String, Object)()
        skipFirstShow = False

        With channel
            info!Logo = .SelectSingleNode(".//img").Attributes("src").Value
            info!Channel = .SelectSingleNode(".//span[@class='channel']").ChildNodes(3).ChildNodes(0).InnerText
            info!Station = .SelectSingleNode(".//span[@class='channel']").ChildNodes(3).ChildNodes(2).InnerText

            Dim style As String = .SelectSingleNode(".//span[2]").Attributes("style").Value

            If InStr(style.ToLower, "width: 0px;") <> 0 Then skipFirstShow = True

            info!Shows = From tag In .SelectNodes(".//a[@class='thickbox']")
                         Select New With {.Show = tag.Attributes("title").Value, .Link = tag.Attributes("href").Value}
            'Select New With {.Show = tag.Attributes("title").Value, .Link = tag.Attributes("href").Value}
        End With

        all.Add(info!Station, info.Item("Shows"))
        theLogoURL(theCount) = "https://xxx.com" & Trim(info.Item("Logo"))
        theChannelNum(theCount) = Trim(info.Item("Channel"))
        theStationCallLetters(theCount) = Trim(info.Item("Station"))

        Dim Shows As String = ""
        Dim ShowsDetail As String = ""
        Dim tmpShows = all.Item(info!Station)

Answer 1

使用Count代替长度。

示例：

Dim showNumber As Integer = tmpShows.Count

Answer 2

我这样做是为了得到我的统计......

 Dim intXShows As Integer = 0

 For Each item In tmpShows
    intXShows += 1
 Next

Answer 3

您是否尝试过这样更改声明：

Dim all as New Dictionary(Of String, Object)()

而不是：

Dim all = New Dictionary(Of String, Object)()

然后拨打Count，Length等等。

还可以尝试使用ForEach循环来计算all变量。