Question

如果我有一个频率字典，其中包含文本中的单词作为键，以及它们在文本中作为值出现的次数。如何通过确保考虑多次出现的单词来获得单词计数和平均长度？现在我所拥有的只是创建一个键列表（因为它们是单词），然后只使用len（）进行字数统计。

wordcount=len(list(freq.keys()))
report["count:"]=wordcount
#for average length:
avg=list(freq.keys())
average=sum(map(len,avg))/len(avg)
report["avglen"]=average

Answer 1

使用sum功能和dict.values()：

freq = { 'test' : 10, 'rep' : 100 }
wordcount = sum(freq.values())
average   = sum(len(w) * c for w, c in freq.items()) / wordcount
print(wordcount, average)

Answer 2

number_of_words  = int(raw_input("Enter the number of words. "))

word_dict = {}

for i in range(number_of_words):
    word = raw_input("Enter word. ")
    if word in word_dict:
        word_dict[word] += 1
    else:
        word_dict[word] = 1

print word_dict

print sum([len(word)*word_dict[word] for word in word_dict])/number_of_words

一个非常相似的问题：https://stackoverflow.com/questions/20143947/word-frequency-counter-python/20145320#20145320

从频率字典中获取字数和平均长度

2 个答案: