标签
tag_id post_id value
------------------------
1 1 some
2 1 good
3 1 title
4 2 some
5 2 good
6 3 some
7 4 good
8 4 title
帖子
post_id title
-------------------
1 some good title
2 some good
3 some
4 good title
我们怎样才能在同一个post_id中获得包含值 some
和good
的post_id = 1和2?
所以结果是
RESULT
title
----------
some good title
some good
good title
剂量显示因为标签中的post_id = 4中没有some
值。
some
并未显示要求good
答案 0 :(得分:3)
多次尝试LIKE
:
SELECT * FROM post
WHERE title LIKE '%some%'
AND title LIKE '%good%'
您也可以像这样加入两个表:
SELECT post.post_id, title FROM Post
RIGHT JOIN Tags
ON post.post_id = tags.post_id
WHERE Tags.value IN ('some','good')
GROUP BY post.Post_ID
HAVING COUNT(*)>1;
注意:如果我们不使用HAVING
子句,它也会返回任何单个值存在的记录