我有类似Facebook的Wall构建在PHP上使用MySQL数据库。
结构:
最后一件事是评论。它们存储在帖子所在的同一个表中,但“回复”行设置为帖子的ID,就像它的“父”一样。
这是一个简单的例子:
Food (category):
-> Kebabs (group)
->-> What's your fave kebab, folks? (post)
->->-> I love doner kebab! (post too, but displayed as comment)
选择相关帖子时遇到麻烦。你看,我需要显示与用户有某种关联的帖子。
目前这些关系是:
我想这将是一个复杂的查询...而且我的知识太短了。
以下是查询:
SELECT `posts`.`id`, `posts`.`created_at`, `posts`.`content`, `posts`.`replies`, `groups`.`id` AS `group_id`, `groups`.`name` AS `group_name`, `users`.`name`, `users`.`surname`, `users`.`avatar`
FROM `posts`
JOIN `groups` ON (`groups`.`id` = `posts`.`group_id`)
JOIN `users` ON (`users`.`id` = `posts`.`user_id`)
WHERE `posts`.`status` = 1 AND `posts`.`post_id` = 0 AND `posts`.`user_id` = '33'
ORDER BY `posts`.`id` DESC
LIMIT 10
OFFSET 0
修改
这是表结构:
CREATE TABLE `bio_community_categories` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
CREATE TABLE `bio_community_groups` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`category_id` int(10) unsigned NOT NULL,
`user_id` int(10) unsigned NOT NULL,
`created_at` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`description` text,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=25 DEFAULT CHARSET=utf8;
CREATE TABLE `bio_community_posts` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(10) unsigned NOT NULL,
`group_id` int(10) unsigned NOT NULL,
`post_id` int(11) unsigned NOT NULL DEFAULT '0',
`created_at` int(11) NOT NULL,
`content` text NOT NULL,
`status` tinyint(1) unsigned NOT NULL DEFAULT '1',
`replies` int(10) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
KEY `status` (`status`),
KEY `post_id` (`post_id`),
KEY `user_id` (`user_id`),
KEY `group_id` (`group_id`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
CREATE TABLE `users` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
`surname` varchar(50) NOT NULL,
/* Etc.. */
PRIMARY KEY (`id`),
) ENGINE=InnoDB DEFAULT CHARSET=utf8;CREATE TABLE `bio_community_categories` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
CREATE TABLE `bio_community_groups` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`category_id` int(10) unsigned NOT NULL,
`user_id` int(10) unsigned NOT NULL,
`created_at` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`description` text,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=25 DEFAULT CHARSET=utf8;
CREATE TABLE `bio_community_posts` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(10) unsigned NOT NULL,
`group_id` int(10) unsigned NOT NULL,
`post_id` int(11) unsigned NOT NULL DEFAULT '0',
`created_at` int(11) NOT NULL,
`content` text NOT NULL,
`status` tinyint(1) unsigned NOT NULL DEFAULT '1',
`replies` int(10) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
KEY `status` (`status`),
KEY `post_id` (`post_id`),
KEY `user_id` (`user_id`),
KEY `group_id` (`group_id`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
CREATE TABLE `users` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
`surname` varchar(50) NOT NULL,
/* Etc.. */
PRIMARY KEY (`id`),
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
答案 0 :(得分:2)
假设也会有组用户关系表,
我们说"groups_members"
所以您的查询将如下,
SELECT `posts`.`id`, `posts`.`created_at`, `posts`.`content`, `posts`.`replies`, `groups`.`id` AS `group_id`, `groups`.`name` AS `group_name`, `users`.`name`, `users`.`surname`, `users`.`avatar`
FROM `posts`
JOIN `groups` ON (`groups`.`id` = `posts`.`group_id`)
JOIN `users` ON (`users`.`id` = `posts`.`user_id`)
WHERE `posts`.`status` = 1 AND `posts`.`post_id` = 0 AND (`posts`.`user_id` = '33' OR `bio_community_posts`.`group_id` IN (SELECT `group_id` FROM `groups_members` WHERE `user_id` =33))
ORDER BY `posts`.`id` DESC
LIMIT 10
OFFSET 0
从上面的查询中,您将获得用户33发布的帖子以及用户33所属的组中的帖子。