Question

我在hive中有以下数据：

userid cityid
1      15
2      15
1      7
3      15
2      8
3      9
3      7

我想只保留具有cityid 15和cityid 7的用户ID（在我的示例中，它将是userid的1和3）。我试过了：

select userid from table where cityid = 15 and userid in (select userid from table where cityid = 7);

但是蜂巢不起作用。有人可以帮忙吗？

谢谢！

Answer 1

好的，我发现了怎么做：

select a.userid from (select userid from table where cityid = 15) a join (select userid from table where cityid = 7) b on a.userid = b.userid;

Answer 2

SELECT DISTINCT userid FROM table_name WHERE cityid == 15 OR cityid == 7;

Answer 3

尝试避免自我加入

SELECT  userid
FROM
 ( SELECT userid, collect_set( cityid) as cities
   FROM table 
   GROUP BY userid 
 )
WHERE array_contains( cities, 7 )
AND array_contains( cities, 15 );

在Hive中获取数据交集

3 个答案: