我有两个基类之间的关系:
public abstract class RecruiterBase<T>
{
// Properties declare here
// Constructors declared here
public abstract IQueryable<T> GetCandidates();
}
public abstract class CandidateBase<T>
{
// Properties declare here
// Constructors declared here
}
他们的具体实施如下:
public class CandidateA : CandidateBase<CandidateA>
{
// Constructors declared here
}
public class RecruiterA : RecruiterBase<RecruiterA>
{
// Constructors declared here
// ----HERE IS WHERE I AM BREAKING DOWN----
public override IQueryable<CandidateA> GetCandidates()
{
return from c in db.Candidates
where c.RecruiterId == this.RecruiterId
select new CandidateA
{
CandidateId = c.CandidateId,
CandidateName = c.CandidateName,
RecruiterId = c.RecruiterId
};
}
}
每个MSDN文档 http://msdn.microsoft.com/en-us/library/ms379564%28VS.80%29.aspx(大约一半) 在SO上有类似的(但不完全相同的)questoin Specifying the return type of an abstract method from a Base Class according to a Sub Class
我可以将我的concreate实现用于我重写的方法GetCandidates的返回类型,但这不是我想要的,我想利用不同抽象类的具体实现。这是父/子数据库关系。我想要达到的目标是什么?我目前得到一个编译时错误,我的GetCandidates返回类型不匹配。
由于
答案 0 :(得分:2)
看起来您需要定义多个泛型类型,其中一个可能被约束为派生自CandidateBase。
尝试这样的事情:
public abstract class RecruiterBase<T, C> where C : CandidateBase
{
// Properties declare here
// Constructors declared here
public abstract IQueryable<C> GetCandidates();
}
public abstract class CandidateBase<T>
{
// Properties declare here
// Constructors declared here
}
public class CandidateA : CandidateBase<CandidateA>
{
// Constructors declared here
}
public class RecruiterA : RecruiterBase<RecruiterA, CandidateA>
{
public override IQueryable<CandidateA> GetCandidates()
{
return from c in db.Candidates
where c.RecruiterId == this.RecruiterId
select new CandidateA
{
CandidateId = c.CandidateId,
CandidateName = c.CandidateName,
RecruiterId = c.RecruiterId
};
}
}
修改包括克里斯的更正