Question

int main(int argc, char *argv[]) {

    int conn_s = socket(AF_INET, SOCK_STREAM, 0);
    struct addrinfo hints;
    hints.ai_family = AF_INET;
    hints.ai_socktype = SOCK_STREAM;
    hints.ai_protocol = 0;

    struct addrinfo *addr = (struct addrinfo *) calloc(1, sizeof(struct addrinfo));

    getaddrinfo("google.com", "80", &hints, &addr);

    connect(conn_s, addr->ai_addr, sizeof(struct sockaddr_in));

    char *http_request = "GET / HTTP/1.1\n\n";

    send(conn_s, http_request, strlen(http_request), 0);
    FILE *sockfile = (FILE *) fdopen(conn_s, "r");
    FILE *fp = fopen("/Users/leekaiwei/Desktop/results.html", "w+");
    int ch;

    while ((ch = fgetc(sockfile)) != EOF) {
        fprintf(fp, "%c", ch);
    }

    close(conn_s);
    fclose(fp);
    fclose(sockfile);
    free(addr);
    return 0;
}

while循环永远不会结束。为什么是这样？我用本地文件完成了它，它工作正常。它也适用于for循环，只是fgetc（）永远不会返回EOF。

Answer 1

HTTP/1.1默认为connection: keepalive，所以像simonc所说的那样，服务器实际上正在等待您发出下一个请求，并将等到服务器相关的超时。使用HTTP/1.0获取EOF。

FWIW：完成需要245秒。

检查EOF时，套接字/文件流上的C fgetc（）进入无限循环

1 个答案: