Question

我正在尝试编写一个给定传递的char指针的方法来更改Out1和Out0的原始值并给出按位比较函数。主文件测试各种值。但是，我一直收到一条错误消息，指出Out1 Out0 fsm生成pointers from integers without a cast，即使我投了它。任何帮助将不胜感激。这是代码。

#include <stdio.h>
#include <stdlib.h>

void fsm(char I1, char I0, char Reset, char *Out1, char *Out0){
    int I1num = I1-'0';
    int I0num = I0-'0';
    int ResetNum = Reset - '0';
    int Out1Num = *Out1 - '0';
    int Out0Num = *Out0 - '0';

    int Out1Final = (Out0Num & !I0num & Out1Num)|(!Out0Num & I0num)|(!Out0Num & !Out1Num)|(I0num & !Out1Num);
    int Out0Final = ((!(Out1Num & I0num) & !(!Out1Num & I0) & !(Out1Num & !(I0))) & !Out0Num) | (!(!((!Out1Num)&(I1num))&!((Out1Num)&(!I0num)))&Out0Num);

    Out1 = (char)(Out1Final);
    Out0 = (char)(Out0Final);
}

/*
 * 
 */
int main(int argc, char** argv) {

    char Out1 = '0';
    char Out0 = '0';
    char *Out1Ptr = &Out1;
    char *Out0Ptr = &Out0;
    fsm('0','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:0, Reset:0, Q1:0, Q0:0. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '0';
    fsm('0','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:0, Reset:0, Q1:1, Q0:0. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '1';
    fsm('0','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:0, Reset:0, Q1:1, Q0:1. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '0';
    Out0 = '1';
    fsm('0','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:0, Reset:0, Q1:0, Q0:1. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );

    Out1 = '0';
    Out0 = '0';
        *Out1Ptr = Out1;
    *Out0Ptr = Out0;
    fsm('1','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:0, Reset:0, Q1:0, Q0:0. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '0';
    fsm('1','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:0, Reset:0, Q1:1, Q0:0. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '1';
    fsm('1','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:0, Reset:0, Q1:1, Q0:1. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );
    Out1 = '0';
    Out0 = '1';
    fsm('1','0','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:0, Reset:0, Q1:0, Q0:1. Out1 is %s and Out0 is %s .", *Out1Ptr, *Out0Ptr );

    Out1 = '0';
    Out0 = '0';
        *Out1Ptr = Out1;
    *Out0Ptr = Out0;
    fsm('0','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:1, Reset:0, Q1:0, Q0:0. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '0';
    fsm('0','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:1, Reset:0, Q1:1, Q0:0. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '1';
    fsm('0','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:1, Reset:0, Q1:1, Q0:1. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '0';
    Out0 = '1';
    fsm('0','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:0, I0:1, Reset:0, Q1:0, Q0:1. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );

    Out1 = '0';
    Out0 = '0';
        *Out1Ptr = Out1;
    *Out0Ptr = Out0;
    fsm('1','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:1, Reset:0, Q1:0, Q0:0. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '0';
    fsm('1','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:1, Reset:0, Q1:1, Q0:0. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '1';
    Out0 = '1';
    fsm('1','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:1, Reset:0, Q1:1, Q0:1. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );
    Out1 = '0';
    Out0 = '1';
    fsm('1','1','0', *Out1Ptr, *Out0Ptr);
    printf("After I1:1, I0:1, Reset:0, Q1:0, Q0:1. Out1 is %c and Out0 is %c .", *Out1Ptr, *Out0Ptr );

    return (EXIT_SUCCESS);
}

Answer 1

即使我投了它。

在哪儿？我没有看到它。我所看到的只是

char *out1Ptr;
char *out0Ptr;

然后

fsm(..., ..., ..., *out1Ptr, *out0Ptr);

这不是一个类型。由于out1Ptr和out0Ptr的类型为char *，因此取消引用它们会生成类型为char的表达式，这是一个整数类型，而fsm()则需要指针为最后两个论点。

所以编译器是对的。

赋值使用Integer指针而不进行强制转换，但有一个强制转换

1 个答案: