我有一个数组
$variables_a = array(
'a' => $a,
'b' => $b,
'c' => $c
);
然后是另一个$variables_b = array('x','y','z')
,我想像这样循环遍历B数组:
foreach($variables_b as $var) {
$variables_c[] = array($var => $$var);
}
然后合并A& C与$variables_combined = array_merge($variables_A, $variables_C)
我希望获得的输出是我print_r
Array
(
[a] => a
[b] => b
[c] => c
[x] => x
[y] => y
[z] => z
)
但我得到的是
Array
(
[a] => a
[b] => b
[c] => c
[0] => Array
(
[x] => x
)
[1] => Array
(
[y] => y
)
[2] => Array
(
[z] => z
)
)
如果我将$feature_variables[] = array($feature => $$feature)
更改为$feature_variables = array($feature => $$feature)
,我会
Array
(
[a] => a
[b] => b
[c] => c
[z] => z
)
即。来自$variables_b
的最后一项,但没有其他项目。那么我哪里出错?
答案 0 :(得分:4)
这样做:
$newvar = $variables_a;
foreach($variables_b as $var)
{
$newvar[$var] = $var;
}
$ newvar将包含您想要的数组
答案 1 :(得分:3)
请循环遍历数组c,如:
foreach($variables_b as $var) {
$variables_c[$var] = $$var;
}
答案 2 :(得分:2)
试试这个,
foreach($variables_b as $var) {
$variables_c[$var] = $$var;
}
答案 3 :(得分:2)
<?php
$variables_a = array(
'a' ,
'b' ,
'c'
);
$variables_b = array('x','y','z');
$variables_c=array();
foreach($variables_a as $var) {
$variables_c[$var] =$var;
}
foreach($variables_b as $var) {
$variables_c[$var] =$var;
}
print_r($variables_c);
?>
============
and test in : "http://codepad.org/1ICZxPIG"
答案 4 :(得分:1)
$variables_a = array(
'a' => $a,
'b' => $b,
'c' => $c
);
$variables_b = array('x','y','z');
foreach($variables_b as $var) {
$variables_c[$var] = $$var;
}
$variables_combined = array_merge($variables_a, $variables_c);
echo "<pre>";print_r($variables_combined);