Question

我有一个我确定是一个简单的问题，但我无法理解。在下面的代码中，我希望能够让案例5在之后重新显示选项。我怎样才能做到这一点？提前谢谢！

// Input the race of your character
    cout << "Choose a race here: " << endl
    << "1) Human, 2) Elf, 3) Dark Dwarf, 4) Commoner, 5) Race info, 6) Admin Debug Race : ";

    cin >> mCharRace;

    switch (mCharRace)
        {
        case 1:
        cout << "You have chosen Human!" << endl;
        mExpPoints = 999;
        mArmor = mArmor + 2;
        break;
    case 2:
        cout << "You have chosen Elf!" << endl;
        mAccuracy = mAccuracy + 2;
        mWeapon.mDamageRange.mLow = mWeapon.mDamageRange.mLow + 1;
        break;
    case 3:
        cout << "You have chosen Dark Dwarf!" << endl;
        mWeapon.mDamageRange.mHigh = mWeapon.mDamageRange.mHigh + 2;
        mMaxHitPoints = mMaxHitPoints + 3;
        break;
    case 4:
        cout << "You have chosen Commoner! Brave man." << endl;
        mAccuracy       = mAccuracy - 3;
        mHitPoints      = mHitPoints - 5;
        mMaxHitPoints   = 8;
        mExpPoints      = -250;
        mNextLevelExp   = 1500;
        mArmor          = -1;
        break;
    case 5:
        cout << "Placeholder for explanation text." << endl;
        break;
    case 6:
        cout << "ADMIN POWERS UNITE!!!!!!!" << endl;
        mAccuracy       = 20;
        mHitPoints      = 1000;
        mMaxHitPoints   = 1000;
        mExpPoints      = 0;
        mNextLevelExp   = 1000;
        mArmor          = 100;
        mWeapon.mName   = "Admin Sword of HNNNG!";
        mWeapon.mDamageRange.mLow   = 100;
        mWeapon.mDamageRange.mHigh  = 150;
        mGold           = 1000000;
        break;

Answer 1

switch-case构造不是迭代构造。它只能选择某个案例并执行它。由于它，控制流程无法恢复。

所以，你不能用它来循环。将其包装在而或用于循环结构中。

while(condition){
   switch (mCharRace){
   ...
   ...
   }
}

如果要停止循环，只需将条件转为 false 即可。

Answer 2

将输入和切换代码包装在循环中，并指定变量exitLoop以退出循环。默认情况下，将该变量设置为TRUE，除非您要重复输入。在那些中，将exitLoop设置为false。

Answer 3

在第一个cout之前添加标签

label:

cout << "Choose a race here: " << endl
<< "1) Human, 2) Elf, 3) Dark Dwarf, 4) Commoner, 5) Race info, 6) Admin Debug Race : ";

cin >> mCharRace;
...

然后在案例5中添加

goto label;

Answer 4

将其置于for(;;)循环内，并使用continue代替break。在break语句结束后添加另一个switch来捕获真正想要破解的案例：

for (;;)
{
    switch (x)
    {
    case case_that_wants_to_loop:
        // ...
        continue;
    case case_that_wants_to_break:
        // ...
        break;
    }
    break;
}

如何在一个case之后循环回一个switch语句的开头

4 个答案: