Question

我目前正在开展一个小型的Arduino项目，我有点卡住了。到目前为止，这是我的代码：

#include "_init.h"

void setup() {
  ds_init();
  Serial.begin(9600);
  randomSeed(analogRead(LIGHT_SENSOR_PIN));

  int rol1[] = {1, 2, 3, 4, 5};
  int rol2[] = {3, 5, 1, 2, 4};
  int rol3[] = {5, 1, 4, 3, 2};

  int rol1Mid = random(0, 5);
  int rol1Bov = rol1Mid + 1;
  int rol1Ond = rol1Mid - 1;

  if (rol1Bov == 5){
    rol1Bov = 0;
  }

  if (rol1Ond == -1){
    rol1Ond = 4;
  }

  int rol2Mid = random(0, 5);
  int rol2Bov = rol2Mid + 1;
  int rol2Ond = rol2Mid - 1;

  if (rol2Bov == 5){
    rol2Bov = 0;
  }

  if (rol2Ond == -1){
    rol2Ond = 4;
  }

  int rol3Mid = random(0, 5);
  int rol3Bov = rol3Mid + 1;
  int rol3Ond = rol3Mid - 1;

  if (rol3Bov == 5){
    rol3Bov = 0;
  }

  if (rol3Ond == -1){
    rol3Ond = 4;
  }  

  Serial.println(rol1[rol1Bov]);
  Serial.println(rol1[rol1Mid]);
  Serial.println(rol1[rol1Ond]);

  Serial.println("----");

  Serial.println(rol2[rol2Bov]);
  Serial.println(rol2[rol2Mid]);
  Serial.println(rol2[rol2Ond]);

  Serial.println("----");

  Serial.println(rol3[rol3Bov]);
  Serial.println(rol3[rol3Mid]);
  Serial.println(rol3[rol3Ond]);

  if(rol1[rol1Mid] && rol2[rol2Mid] == rol3[rol3Mid]){
    Serial.println("Yaay!");
  } else {
    Serial.println("Jammer, probeer het nogmaals.");
  }
  /*
  if(rol1[positieBov] && rol2[positieBov] == rol3[positieBov]){
    Serial.println("Yaay!");
  } else {
    Serial.println("Jammer, probeer het nogmaals.");
  }

  if(rol1[positieOnd] && rol2[positieOnd] == rol3[positieOnd]){
    Serial.println("Yaay!");
  } else {
    Serial.println("Jammer, probeer het nogmaals.");
  }
  */
}

void loop() {
  // put your main code here, to run repeatedly: 

}

基本上，我正在尝试创建一台老虎机。我的代码可能有很多问题，但目前我仍然坚持使用if语句检查用户是否获胜。

我知道我不应该在Arduino的setup（）部分编码，但是一旦这一切都有效，我将把它放在loop（）中的一个函数中，我将使用我的dangershield的按钮来分别操作三卷。

Answer 1

好的，设法解决它......我现在感到愚蠢

if(rol1[rol1Mid] == rol2[rol2Mid] && rol2[rol2Mid] == rol3[rol3Mid])

if中的三个陈述

1 个答案: