VBA-“ IF语句”中嵌套的“ With语句”

时间:2018-06-27 16:20:34

标签: if-statement access-vba with-statement user-defined-types

语言:VBA-MS Access

我在代码中使用了用户定义类型(UDT)。 我希望能够根据状态变量确定将数据加载到UDT的哪个部分。我的第一个尝试是使用嵌套在“ IF”语句中的“ With”语句。这是行不通的(我收到一个编译错误,提示“ Else if if”)。有没有办法使这项工作?还是使用状态变量来确定我正在加载UDT的哪一部分的另一种方式?

Type MyOtherType
    Name as String
    Age as Integer    
End Type

Type MyType
    aMyOtherType() as MyOtherType
    X as Integer
    Y as Integer
    Z as Integer  
End Type

Sub QuestionableCode()
Dim UDT(0 To 0) as MyType
Dim State as String
ReDim Preserve UDT(0).X(0 to 0) as MyOtherType
ReDim Preserve UDT(0).Y(0 to 0) as MyOtherType
ReDim Preserve UDT(0).Z(0 to 0) as MyOtherType

    State = "B"

    If State = "A" Then
        With UDT(0).X(0)
    ElseIf State = "B" Then
        With UDT(0).Y(0)
    Else 
        With UDT(0).Z(0)
    End If
            .Name = "George"
            .Age = 30
        End With
End Sub

1 个答案:

答案 0 :(得分:1)

您不能以这种方式使用With。编译器不允许这种有条件的嵌套代码。不使用With,不使用For,不使用其他任何东西。

但是,您可以使用变量来确定要在其中使用的值:

Sub QuestionableCode()
    Dim UDT(0 To 0) as MyType
    Dim State as String
    ReDim Preserve UDT(0).X(0 to 0) as MyOtherType
    ReDim Preserve UDT(0).Y(0 to 0) as MyOtherType
    ReDim Preserve UDT(0).Z(0 to 0) as MyOtherType

    State = "B"
    Dim myWithVariable
    If State = "A" Then
        myWithVariable = UDT(0).X(0)
    ElseIf State = "B" Then
        myWithVariable = UDT(0).Y(0)
    Else 
        myWithVariable = UDT(0).Z(0)
    End If
    With myWithVariable 
        .Name = "George"
        .Age = 30
    End With
End Sub