使用子查询选择每个学生的出勤率的SQL查询不能使用父查询中的行

时间:2012-10-23 10:05:15

标签: mysql sql subquery

我在SQL中遇到问题,我正在尝试在我正在构建的注册系统中计算出一个班级的学生,但是它不会让我在子查询中使用父列,

SELECT A.student_id, TRUNCATE((100 - ((100/B.reg_num) * C.abs_num)), 0) AS attendance FROM
students A
JOIN (
SELECT COUNT(*) AS reg_num
FROM students
JOIN seminargroup_student ON seminargroup_student.student_id = students.student_id
JOIN seminar_group ON seminar_group.seminar_group_id = seminargroup_student.seminar_group_id
JOIN modules ON modules.module_id = seminar_group.seminar_group_module_id
JOIN register_seminar ON register_seminar.seminar_id = seminar_group.seminar_group_id
JOIN registers ON registers.register_id = register_seminar.register_id
WHERE modules.module_id =1 AND students.student_id = A.student_id
) B
JOIN (
SELECT COUNT(*) AS abs_num
FROM students
JOIN seminargroup_student ON seminargroup_student.student_id = students.student_id
JOIN seminar_group ON seminar_group.seminar_group_id = seminargroup_student.seminar_group_id
JOIN modules ON modules.module_id = seminar_group.seminar_group_module_id
JOIN absence ON students.student_id = absence.student_id
WHERE modules.module_id =1 AND students.student_id = A.student_id
) C

返回:#1054 - 'where子句'中的未知列'A.student_id'

感谢您的帮助!

2 个答案:

答案 0 :(得分:1)

  

它不会让我使用子查询中的父列

一般来说,您不需要在FROM中的子查询中引用父项。

相反,您只需将加入字段添加到子查询中的SELECTGROUP BY子句中,然后加入

e.g。

SELECT students.student_id, 
       Truncate(( 100 - ( ( 100 / b.reg_num ) * c.abs_num ) ), 0) AS attendance 
FROM   students 
       JOIN (SELECT a.studentid, 
                    Count(*) AS reg_num 
             FROM   students A 
                    JOIN seminargroup_student 
                      ON seminargroup_student.student_id = A.student_id 
                    JOIN seminar_group 
                      ON seminar_group.seminar_group_id = 
                         seminargroup_student.seminar_group_id 
                    JOIN modules 
                      ON modules.module_id = 
                         seminar_group.seminar_group_module_id 
                    JOIN register_seminar 
                      ON register_seminar.seminar_id = 
                         seminar_group.seminar_group_id 
                    JOIN registers 
                      ON registers.register_id = register_seminar.register_id 
             GROUP  BY a.studentid) A 
         ON students.studentid = a.student.id 
       JOIN (SELECT a.studentid, 
                    Count(*) AS abs_num 
             FROM   students aA 
                    JOIN seminargroup_student 
                      ON seminargroup_student.student_id = a.student_id 
                    JOIN seminar_group 
                      ON seminar_group.seminar_group_id = 
                         seminargroup_student.seminar_group_id 
                    JOIN modules 
                      ON modules.module_id = 
                         seminar_group.seminar_group_module_id 
                    JOIN absence 
                      ON a.student_id = absence.student_id 
             GROUP  BY a.studentid) b 
         ON students.studentid = b.student.id 

作为旁注,如果使用左连接并且在PK字段上执行DISTINCT COUNT而不是在*

上,则不必执行两个子查询
SELECT 
    A.student_id, 
    TRUNCATE((100 - ((100/counts.reg_num) * counts.abs_num)), 0) AS attendance
FROM
students A   
JOIN 
(SELECT 
    COUNT(DISTINCT absence.absence_id) AS abs_num , --OR whatever the PK is
    COUNT(DISTINCT registers.regeister_id) as reg_num,
    students.student_id


FROM   students 
       JOIN seminargroup_student 
         ON seminargroup_student.student_id = students.student_id 
       JOIN seminar_group 
         ON seminar_group.seminar_group_id = 
            seminargroup_student.seminar_group_id 
       JOIN modules 
         ON modules.module_id = seminar_group.seminar_group_module_id 

       LEFT JOIN register_seminar 
         ON register_seminar.seminar_id = seminar_group.seminar_group_id 
       LEFT JOIN registers 
         ON registers.register_id = register_seminar.register_id   


       LEFT JOIN absence 
         ON students.student_id = absence.student_id 
GROUP BY
    students.student_id) COUNTS
ON a.student_id = coutnts.student_ID    

答案 1 :(得分:0)

尝试将查询重写为:

SELECT students.student_id, TRUNCATE((100 - ((100/B.reg_num) * C.abs_num)), 0) AS attendance FROM 
students 
JOIN ( 
SELECT COUNT(*) AS reg_num 
FROM students A
JOIN seminargroup_student ON seminargroup_student.student_id = A.student_id 
JOIN seminar_group ON seminar_group.seminar_group_id = seminargroup_student.seminar_group_id 
JOIN modules ON modules.module_id = seminar_group.seminar_group_module_id 
JOIN register_seminar ON register_seminar.seminar_id = seminar_group.seminar_group_id 
JOIN registers ON registers.register_id = register_seminar.register_id 
HAVING modules.module_id =1 AND students.student_id = A.student_id 
) B 
JOIN ( 
SELECT COUNT(*) AS abs_num 
FROM students A
JOIN seminargroup_student ON seminargroup_student.student_id = A.student_id 
JOIN seminar_group ON seminar_group.seminar_group_id = seminargroup_student.seminar_group_id 
JOIN modules ON modules.module_id = seminar_group.seminar_group_module_id 
JOIN absence ON A.student_id = absence.student_id 
HAVING modules.module_id =1 AND students.student_id = A.student_id 
) C

UPD :WHERE子句替换为HAVING,别名在子查询中移动。 由于在SELECT之前计算了WHERE,可能会导致错误。

这些问题也可以帮助您解决问题:
1。 Unknown Column In Where Clause
2。 WHERE vs HAVING