我在下面的查询中提取了参加体育或学校活动的学生的每日出勤率（1到10期）。我只想看到其中一个时期至少有一个缺席的学生，所以如果所有时期的出勤代码都是NULL，则不应出现。我不知道如何将其添加到查询中。有人可以帮忙吗？
SELECT DISTINCT
s.student_number AS "Student Number",
s.lastfirst AS "Student Name",
DECODE(s.grade_level,-1,'PK',0,'KG',s.grade_level) AS "Grade",
s.home_phone AS "Phone",
DECODE(s.schoolid,280050,'Kodiak High School',s.schoolid) AS "School",
(SELECT DISTINCT co.course_name FROM ps.courses WHERE co.course_number=se.course_number AND se.course_number LIKE 'CLB%' OR se.course_number LIKE 'ACT%') AS "Course Name",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='1') AS "Per. 1",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='2') AS "Per. 2",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='3') AS "Per. 3",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='4') AS "Per. 4",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='5') AS "Per. 5",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='6') AS "Per. 6",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='7') AS "Per. 7",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='8') AS "Adv",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='9') AS "Act",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='10') AS "Clb"
FROM attendance att
JOIN students s ON s.id=att.studentid
INNER JOIN cc ON s.ID=cc.studentid
INNER JOIN sections se ON cc.sectionid = se.id
JOIN courses co ON co.course_number=se.COURSE_NUMBER
WHERE att.att_date=to_date(SYSDATE)
AND att.schoolid in '280050'
AND s.enroll_status=0
AND cc.termid = 2700
AND se.course_number LIKE 'ACT%'OR se.course_number LIKE 'CLB%'
ORDER BY s.lastfirst
以下是数据示例。所有句点都为NULL时，我不希望看到行。只有他们有缺席代码。Data Sample
答案 0 :(得分：0)
虽然我对你正在处理的数据知之甚少，但我想建议这是一个起点：
SELECT
studentid
, max(case when period_number='1' then attcodes end) per1
, max(case when period_number='2' then attcodes end) per2
, max(case when period_number='3' then attcodes end) per3
, max(case when period_number='4' then attcodes end) per4
, max(case when period_number='5' then attcodes end) per5
, max(case when period_number='6' then attcodes end) per6
, max(case when period_number='7' then attcodes end) per7
, max(case when period_number='8' then attcodes end) per8
, max(case when period_number='9' then attcodes end) per9
, max(case when period_number='10' then attcodes end) per10
FROM (
SELECT
attm.studentid
, attm.period_number
, listagg(attm.att_code,'|') within group (order by attm.att_code) attcodes
FROM pssis_attendance_meeting attm
WHERE attm.att_date=to_date(SYSDATE)
AND attm.att_code IS NOT NULL
GROUP BY
attm.studentid
, attm.period_number
) d
GROUP BY
studentid
;
这将为每位学生生成一行，其中包含10列出勤代码。我不知道为什么你会在一段时间内有多个出勤代码，但我继续使用listagg（）以防万一。
在此查询中，逻辑会删除当天未注册出席代码的所有学生。
我希望这可以帮助您找到整体解决方案。
Oracle 11g R2架构设置：
CREATE TABLE PSSIS_ATTENDANCE_MEETING
(NAME varchar2(15), STUDENT_NUMBER int
, CURRENT_GRADE_LEVEL int
, CURRENT_SCHOOL_ABBREVIATION varchar2(3)
, GENDER varchar2(1)
, ETHNICITY_NAME varchar2(4), ETHNICITY_CODE int
, SPECIAL_ED_STUDENT varchar2(2), ID int, STUDENTID int, SCHOOLID int
, ATT_DATE timestamp, ATTENDANCE_CODEID int, ATT_CODE varchar2(3)
, ATT_MODE_CODE varchar2(15), ATT_INTERVAL int, CALENDAR_DAYID int
, CCID int, ATT_COMMENT int, CC_SCHOOLID int, DROPPED int, PERIODID int
, PERIOD_ABBREVIATION varchar2(2), PERIOD_NUMBER int, SECTIONID int
, SECTION_NUMBER int, PROGRAMID int, PROGRAM_NAME int, TRACK_A int
, TRACK_B int, TRACK_C int, TRACK_D int, TRACK_E int, TRACK_F int
, INSESSION int, COUNT_FOR_ADA int, PRESENCE_STATUS_CD varchar2(6)
, CYCLE_DAY_ID int, CYCLE_DAY_ABBREVIATION varchar2(2), TOTAL_MINUTES int)
;
INSERT ALL
INTO PSSIS_ATTENDANCE_MEETING (NAME, STUDENT_NUMBER, CURRENT_GRADE_LEVEL, CURRENT_SCHOOL_ABBREVIATION, GENDER, ETHNICITY_NAME, ETHNICITY_CODE, SPECIAL_ED_STUDENT, ID, STUDENTID, SCHOOLID, ATT_DATE, ATTENDANCE_CODEID, ATT_CODE, ATT_MODE_CODE, ATT_INTERVAL, CALENDAR_DAYID, CCID, ATT_COMMENT, CC_SCHOOLID, DROPPED, PERIODID, PERIOD_ABBREVIATION, PERIOD_NUMBER, SECTIONID, SECTION_NUMBER, PROGRAMID, PROGRAM_NAME, TRACK_A, TRACK_B, TRACK_C, TRACK_D, TRACK_E, TRACK_F, INSESSION, COUNT_FOR_ADA, PRESENCE_STATUS_CD, CYCLE_DAY_ID, CYCLE_DAY_ABBREVIATION,TOTAL_MINUTES)
VALUES ('used_by_already', 999999, 1, 'OHS', 'F', NULL, 6, 'No', 7240947, 40576, 280100, '14-Dec-2017 12:00:00 AM', 4345, 'EXA', 'ATT_ModeMeeting', 0, 97488, 790700, NULL, 280100, 0, 5731, 'AM', 1, 66373, 1, 0, NULL, 1, 1, 1, 1, 1, 1, 1, 1, 'Absent', 3214, 'TH', 0)
INTO PSSIS_ATTENDANCE_MEETING (NAME, STUDENT_NUMBER, CURRENT_GRADE_LEVEL, CURRENT_SCHOOL_ABBREVIATION, GENDER, ETHNICITY_NAME, ETHNICITY_CODE, SPECIAL_ED_STUDENT, ID, STUDENTID, SCHOOLID, ATT_DATE, ATTENDANCE_CODEID, ATT_CODE, ATT_MODE_CODE, ATT_INTERVAL, CALENDAR_DAYID, CCID, ATT_COMMENT, CC_SCHOOLID, DROPPED, PERIODID, PERIOD_ABBREVIATION, PERIOD_NUMBER, SECTIONID, SECTION_NUMBER, PROGRAMID, PROGRAM_NAME, TRACK_A, TRACK_B, TRACK_C, TRACK_D, TRACK_E, TRACK_F, INSESSION, COUNT_FOR_ADA, PRESENCE_STATUS_CD, CYCLE_DAY_ID, CYCLE_DAY_ABBREVIATION,TOTAL_MINUTES)
VALUES ('used_by_already', 999999, 1, 'OHS', 'F', NULL, 6, 'No', 7240948
, 40576, 280100, '14-Dec-2017 12:00:00 AM', 4345
, 'EXA', 'ATT_ModeMeeting', 0, 97488, 790696, NULL
, 280100, 0, 5732, 'PM', 2, 66427, 1, 0, NULL
, 1, 1, 1, 1, 1, 1, 1, 1, 'Absent', 3214, 'TH'
, 0)
SELECT * FROM dual
;
查询1 ：
SELECT
attm.studentid
, attm.period_number
, listagg(attm.att_code,'|') within group (order by attm.att_code) attcodes
FROM pssis_attendance_meeting attm
WHERE attm.att_date=to_date('14-Dec-2017')
AND attm.att_code IS NOT NULL
GROUP BY
attm.studentid
, attm.period_number
;
<强> Results ：
| STUDENTID | PERIOD_NUMBER | ATTCODES |
|-----------|---------------|----------|
| 40576 | 1 | EXA |
| 40576 | 2 | EXA |
查询2 ：
SELECT
studentid
, max(case when period_number='1' then attcodes end) per1
, max(case when period_number='2' then attcodes end) per2
, max(case when period_number='3' then attcodes end) per3
, max(case when period_number='4' then attcodes end) per4
, max(case when period_number='5' then attcodes end) per5
, max(case when period_number='6' then attcodes end) per6
, max(case when period_number='7' then attcodes end) per7
, max(case when period_number='8' then attcodes end) per8
, max(case when period_number='9' then attcodes end) per9
, max(case when period_number='10' then attcodes end) per10
FROM (
SELECT
attm.studentid
, attm.period_number
, listagg(attm.att_code,'|') within group (order by attm.att_code) attcodes
FROM pssis_attendance_meeting attm
WHERE attm.att_date=to_date('14-Dec-2017')
AND attm.att_code IS NOT NULL
GROUP BY
attm.studentid
, attm.period_number
) d
GROUP BY
studentid
<强> Results ：
| STUDENTID | PER1 | PER2 | PER3 | PER4 | PER5 | PER6 | PER7 | PER8 | PER9 | PER10 |
|-----------|------|------|--------|--------|--------|--------|--------|--------|--------|--------|
| 40576 | EXA | EXA | (null) | (null) | (null) | (null) | (null) | (null) | (null) | (null) |
答案 1 :(得分：0)
感谢您的耐心等待！我的下面的查询旨在为参加活动/体育活动的学生提供所有时段的出勤率。现在我只想在一个或多个时段内缺席时显示记录。我尝试添加attm.att_code IS NOT NULL但我无法找到一种方法在所有时段都这样做，所以显然不起作用。我可以为参加多项运动/活动的学生获得多行，但两行的出勤率相同。
我还想通过体育/活动对出席情况进行分组，但是当我在查询结束时添加GROUP BY co.course_name时，它也无法正常工作。
SELECT DISTINCT
s.student_number AS "Student Number",
s.lastfirst AS "Student Name",
DECODE(s.grade_level,-1,'PK',0,'KG',s.grade_level) AS "Grade",
s.home_phone AS "Phone",
DECODE(s.schoolid,280050,'Kodiak High School',s.schoolid) AS "School",
(SELECT DISTINCT co.course_name FROM ps.courses WHERE co.course_number=se.course_number AND se.course_number LIKE 'CLB%' OR se.course_number LIKE 'ACT%') AS "Course",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='1') AS "Per. 1",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='2') AS "Per. 2",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='3') AS "Per. 3",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='4') AS "Per. 4",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='5') AS "Per. 5",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='6') AS "Per. 6",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='7') AS "Per. 7",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='8') AS "Adv",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='9') AS "Act",
(SELECT listagg(attm.att_code,'|') within group (order by attm.att_code) FROM pssis_attendance_meeting attm WHERE attm.att_date=to_date(SYSDATE) AND attm.studentid=s.id AND attm.att_code IS NOT NULL AND attm.period_number='10') AS "Clb"
FROM attendance att
JOIN students s ON s.id=att.studentid
INNER JOIN cc ON s.ID=cc.studentid
INNER JOIN sections se ON cc.sectionid = se.id
JOIN courses co ON co.course_number=se.COURSE_NUMBER
WHERE att.att_date=to_date(SYSDATE)
AND att.schoolid in '280050'
AND s.enroll_status=0
AND cc.termid = 2700
AND se.course_number LIKE 'ACT%'OR se.course_number LIKE 'CLB%'
ORDER BY s.lastfirst
答案 2 :(得分：0)
显然你不明白我的想法。拿我提供的提出新查询看起来有点像这样：
SELECT
s.*, att.* -- choose which columns you want, form these sources or other you can add to it
from students AS s
INNER JOIN (
SELECT
studentid
, max(case when period_number='1' then attcodes end) per1
, max(case when period_number='2' then attcodes end) per2
, max(case when period_number='3' then attcodes end) per3
, max(case when period_number='4' then attcodes end) per4
, max(case when period_number='5' then attcodes end) per5
, max(case when period_number='6' then attcodes end) per6
, max(case when period_number='7' then attcodes end) per7
, max(case when period_number='8' then attcodes end) per8
, max(case when period_number='9' then attcodes end) per9
, max(case when period_number='10' then attcodes end) per10
FROM (
SELECT
attm.studentid
, attm.period_number
, listagg(attm.att_code,'|') within group (order by attm.att_code) attcodes
FROM pssis_attendance_meeting attm
WHERE attm.att_date=to_date('14-Dec-2017')
AND attm.att_code IS NOT NULL
GROUP BY
attm.studentid
, attm.period_number
) d
GROUP BY
studentid
) AS att on s.studentid = att.studentid
您可以在任何地方选择所需的列，但如果您使用我给您的子查询，则使用INNER JOIN它将解决＆＃34; not null＆＃34;问题。
请告诉我你现在明白了。
答案 3 :(得分：0)
SELECT
s.student_number AS "Student Number"
, s.lastfirst AS "Student Name"
, DECODE(s.grade_level, - 1, 'PK', 0, 'KG', s.grade_level) AS "Grade"
, s.home_phone AS "Phone"
, DECODE(s.schoolid, 280050, 'Kodiak High School', s.schoolid) AS "School"
, att.*
FROM (
SELECT
studentid
, max(case when period_number='1' then attcodes end) per1
, max(case when period_number='2' then attcodes end) per2
, max(case when period_number='3' then attcodes end) per3
, max(case when period_number='4' then attcodes end) per4
, max(case when period_number='5' then attcodes end) per5
, max(case when period_number='6' then attcodes end) per6
, max(case when period_number='7' then attcodes end) per7
, max(case when period_number='8' then attcodes end) per8
, max(case when period_number='9' then attcodes end) per9
, max(case when period_number='10' then attcodes end) per10
FROM (
SELECT
attm.studentid
, attm.period_number
, listagg(attm.att_code,'|') within group (order by attm.att_code) attcodes
FROM pssis_attendance_meeting attm
WHERE attm.att_date=trunc(sysdate)
AND attm.att_code IS NOT NULL
AND attm.schoolid IN '280050'
GROUP BY
attm.studentid
, attm.period_number
) d
GROUP BY
studentid
) att
INNER JOIN students s ON s.id = att.studentid
INNER JOIN cc ON s.ID = cc.studentid
INNER JOIN sections se ON cc.sectionid = se.id
INNER JOIN courses co ON co.course_number = se.COURSE_NUMBER
WHERE s.enroll_status = 0 AND cc.termid = 2700 AND se.course_number LIKE 'ACT%' OR se.course_number LIKE 'CLB%'
ORDER BY s.lastfirst