Question

我有如下表，
我想找到max（account_opened_date），如果存在null date，我必须显示空值。

场景1

表1

CLIENTID            ACCOUNTID           ACCOUNT_OPENED_DATE
11562               3880                07/05/2012
11562               3884                08/05/2012
11562               3885                09/06/2012
11562               3886                10/06/2012
11562               3881                NULL
11562               3882                NULL

结果如下。

CLIENTID            ACCOUNTID           ACCOUNT_OPENED_DATE  
11562               3882                NULL

在上面的场景中，我必须取null，因为帐户开立日期中存在空值

场景2

表1

CLIENTID            ACCOUNTID           ACCOUNT_OPENED_DATE  
11563               3880                07/05/2012
11563               3884                08/05/2012
11563               3885                09/06/2012
11563               3886                10/06/2012
11563               3881                11/10/2011
11563               3882                10/22/2012

结果如下。

CLIENTID            ACCOUNTID           ACCOUNT_OPENED_DATE
11563               3882                10/22/2012

在上面的场景中，我必须采取10/22/2012因为，帐户开立日期中不存在空值
请帮助！

Answer 1

您可以选择TOP 1获取一条记录，并选择ORDER BY CASE作为“空优先”要求：

SELECT TOP 1 CLIENTID, ACCOUNTID, ACCOUNT_OPENED_DATE
FROM dbo.Table
ORDER BY CASE WHEN ACCOUNT_OPENED_DATE IS NULL THEN 0 ELSE 1 END ASC
  , ACCOUNT_OPENED_DATE DESC
  , ACCOUNTID DESC

场景1小提琴：http://sqlfiddle.com/#!3/b7906/1/0
场景2小提琴：http://sqlfiddle.com/#!3/752db/1/0

Answer 2

试试这个

SELECT * FROM (
SELECT CLIENTID, ACCOUNTID, ACCOUNT_OPENED_DATE, 
ROW_NUMBER() OVER (partition by clientid 
             ORDER BY CASE WHEN ACCOUNT_OPENED_DATE IS NULL THEN '12/31/9999' 
                      ELSE ACCOUNT_OPENED_DATE END DESC) opened_date_rank
FROM dbo.Table1
) v WHERE opened_date_rank = 1

示例：

declare @table table (clientid int, accountid int, opened_date date)
insert into @table 
select 11562, 3880, '07/05/2012' UNION ALL
select 11562,3884, '08/05/2012' UNION ALL
select 11562,3882, null UNION ALL
select 11563,3880, '07/05/2012' UNION ALL
select 11563,3884, '08/05/2012' UNION ALL
select 11563,3882,'10/22/2012'



SELECT * FROM (
SELECT clientid, accountid, opened_date, 
row_number() over (partition by clientid 
             ORDER BY CASE WHEN opened_date IS NULL THEN '12/31/9999' 
                      ELSE opened_date END DESC) opened_date_rank
FROM @table
) v where opened_date_rank = 1

SQL Server 2008查询以拉开最大帐户日期

2 个答案: