SQL Query获取每年的最小和最大日期日期范围

Question

目前我有一个查询，它正在加载给定租户的每年销售额。使用下面的代码，我可以产生这个结果（见图表）

SELECT DATENAME(month,date) [month]
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year1 THEN gsc END), 0) AS 'Year1'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year2 THEN gsc END), 0) AS 'Year2'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year3 THEN gsc END), 0) AS 'Year3'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year4 THEN gsc END), 0) AS 'Year4'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year5 THEN gsc END), 0) AS 'Year5'
INTO #LRSalesAnalysis
FROM dailymod 
WHERE tenantcode = @RP 
GROUP BY DATENAME(month,date)
ORDER BY DATEPART(MM,DATENAME(month,date)+' 01 2011')

部分代码，请注意参数@ Year1-5的值类似于（2011,2012等）

结果

我现在想要的是获得每年的最短日期和最长日期。导致像这样的东西

源数据库实际上是每个日期的销售集合。所以我想获得在给定日期范围（年）中找到的最大和最小日期

非常感谢任何帮助

Answer 1

这是使用您已经使用的相同技术完成的。只有两个查询，一个用于min，一个用于max，您将与UNION ALL粘合在一起。

SELECT 
  'Min Date' AS what
  ,MIN(CASE WHEN YEAR(DATE) = @Year1 THEN DATE END) AS 'Year1'
  ,MIN(CASE WHEN YEAR(DATE) = @Year2 THEN DATE END) AS 'Year2'
  ,MIN(CASE WHEN YEAR(DATE) = @Year3 THEN DATE END) AS 'Year3'
  ,MIN(CASE WHEN YEAR(DATE) = @Year4 THEN DATE END) AS 'Year4'
  ,MIN(CASE WHEN YEAR(DATE) = @Year5 THEN DATE END) AS 'Year5'
FROM dailymod 
WHERE tenantcode = @RP 
UNION ALL
SELECT
  'Max Date' AS what
  ,MAX(CASE WHEN YEAR(DATE) = @Year1 THEN DATE END) AS 'Year1'
  ,MAX(CASE WHEN YEAR(DATE) = @Year2 THEN DATE END) AS 'Year2'
  ,MAX(CASE WHEN YEAR(DATE) = @Year3 THEN DATE END) AS 'Year3'
  ,MAX(CASE WHEN YEAR(DATE) = @Year4 THEN DATE END) AS 'Year4'
  ,MAX(CASE WHEN YEAR(DATE) = @Year5 THEN DATE END) AS 'Year5'
FROM dailymod 
WHERE tenantcode = @RP;