我的问题:这是非常具体的。我正在考虑解析以下文本的最简单方法:
^^domain=domain_value^^version=version_value^^account_type=account_type_value^^username=username_value^^password=password_value^^type=type_value^^location=location_value^^id=xxx^^cuid=cuid_value^^
每次都会出现这样的情况。一些要求:
我正在寻找类似这样的代码:
private String[] getKeyValueInfo(String allStuff) {
String domain = someAwesomeMethod("domain", allStuff);
String version = someAwesomeMethod("version", allStuff);
String account_type = someAwesomeMethod("account_type", allStuff);
String username = someAwesomeMethod("username", allStuff);
String password = someAwesomeMethod("password", allStuff);
String type = someAwesomeMethod("password", allStuff);
String location = someAwesomeMethod("location", allStuff);
String id = someAwesomeMethod("id", allStuff);
String cuid = someAwesomeMethod("cuid", allStuff);
return new String[] {domain, version, account_type, username, password, type, location, id, cuid};
}
我不知道的是someAwesomeMethod(String key, String allStuff)
应包含的内容。
我在想什么:这样的事情:
private String someAwesomeMethod(String key, String allStuff) {
Pattern patt = Pattern.compile("(?i)^^" + key + "=(.*?)^^", Pattern.DOTALL);
Matcher matcher = patt.matcher(allStuff);
if (matcher.find()) {
return matcher.group(1);
}
return null;
}
这有什么问题:
如果我不得不这么做,我担心这会有点慢/笨重。所以我正在寻找任何提示/建议。
答案 0 :(得分:5)
如果你必须做很多事情,我会制作一张地图,就像
一样Map<String, String> m = new HashMap<String, String>();
for (String s : stuff.split("\\^\\^")) // caret needs escaping
{
String[] kv = s.split("=");
m.put(kv[0]) = kv[1];
}
然后查找您刚刚执行的密钥m.get("key")
答案 1 :(得分:0)
String.split()适用于
strVar = /* Your big long string */
String[] vars = strVar.split("\\^\\^"); // needs escaping