Question

我有2个型号：

class Professors(models.Model):
    professors_name = models.CharField('professor', max_length=32, unique=True)
class Discipline(models.Model):
    auditorium = models.IntegerField('auditorium')
    professors_name = models.ForeignKey(Professors)

观点：

disciplines = Discipline.objects.all()

所以，我有很多礼堂和教授名_id。但我需要完整的profrssors名称，而不是id。怎么做？

Answer 1

Django ORM将始终返回对象而不是id。你应该有这样的设计。

class Professor(models.Model):
    name = models.CharField('professor', max_length=32, unique=True)
class Discipline(models.Model):
    auditorium = models.IntegerField('auditorium')
    professor = models.ForeignKey(Professors)

并使用discipline.professor.name单独检索名称。

Answer 2

型号：

# models usually named in the singular
class Professor(models.Model):
    professors_name = models.CharField('professor', max_length=32, unique=True) 
class Discipline(models.Model):
    auditorium = models.IntegerField('auditorium')
    # your pointer is to a professor, not to the name
    professor = models.ForeignKey(Professor)

在视图中：

# select_related('professor') to avoid a second query when accessing professor
disciplines = Discipline.objects.select_related('professor')

模板：

{% for disc in disciplines %}
{{ disc.auditorium }}: {{ disc.professor.name }}
{% endfor %}

对于值：

Discipline.objects.values('auditorium', 'professor__name')

django的子查询

2 个答案: