Question

我必须生成介于11到20之间的随机数并将其存储在按钮中。每次生成随机数并在iPhone中随机抽取两个图像的时间例如，如果随机数为12，则图像滑动12次，然后滑动将停止。

我已经生成了随机数，但无法使用随机数滑动图像。

这是我的代码

-(IBAction)btngeneratePressed:(id)sender{



number = 1 + arc4random() % 10 + 10;


for (int j=1;j<number-1;j++)  // generate unique random number only once
{



    NSArray *myImageNames = [NSArray arrayWithObjects:@"1.png", @"2.png", nil];
    //int index = arc4random() % [myImageNames count];

    int index = arc4random() % 2;

    UIImage *myImage = [UIImage imageNamed:[myImageNames objectAtIndex:index]];
    img.image = myImage;




    if(number == j){

        NSLog(@"Number %d ",j);

        UIAlertView *someError = [[UIAlertView alloc] initWithTitle: @"Rendom number" message: @"Image swip" delegate: self cancelButtonTitle: @"Ok" otherButtonTitles: nil];

        [someError show];
        [someError release];
        break;


    }

}
}


- (void)viewDidLoad
{

    number = 1 + arc4random() % 10 + 10;


    NSString *string=[NSString stringWithFormat:@"%i",number];


    int p=string;




    label.text = string;




    for(int j=1;j<number-1;j++)

    {   



        UISwipeGestureRecognizer *recognizer = [[UISwipeGestureRecognizer alloc] initWithTarget:self 
                                                                                         action:@selector(btngeneratePressed:)]; 
        [recognizer setDirection:(UISwipeGestureRecognizerDirectionLeft)];
        recognizer.numberOfTouchesRequired = 1;
        recognizer.direction=UISwipeGestureRecognizerDirectionLeft;
        [self.view addGestureRecognizer:recognizer];
        [recognizer release];    

        //Add a right swipe gesture recognizer
        recognizer = [[UISwipeGestureRecognizer alloc] initWithTarget:self 
                                                               action:@selector(btngeneratePressed:)];
        recognizer.numberOfTouchesRequired = 1;
        recognizer.delegate = self;

        [recognizer setDirection:(UISwipeGestureRecognizerDirectionRight)];
        [self.view addGestureRecognizer:recognizer];
        [recognizer release]; 


        if(number == j){

            NSLog(@"Number %d ",j);

            UIAlertView *someError = [[UIAlertView alloc] initWithTitle: @"Rendom number" message: @"Image swip" delegate: self cancelButtonTitle: @"Ok" otherButtonTitles: nil];

            [someError show];
            [someError release];
            break;

        }




    }


}

Answer 1

我并不完全明白你想要做什么，但是我会把它分成几块来解决问题，而不是试图一次性完成这一切，而且所有这些都混乱了。

将psedo-random唯一编号生成器排序为一次任务，并将其封装在类/方法中。弄清楚如何滑动图像并捕获/计数单个，然后多次滑动整理图像显示将它们连接在一起

现在你正在生成数字1滑动手势识别器，这绝对不对。你想要其中一个。

每次调用btngeneratePressed时，你都会重新生成所有图像：这绝对是低效的，而且很慢。

将问题分解为不连续的部分并解决每个部分，以构建您需要的最终解决方案。

在iPhone中随机图像滑动

1 个答案: