Question

我想知道如何获取列表，ex a = [1,5,2,5,1]，并让它过滤掉唯一值，这样它只返回一个只在列表中出现一次的数字。所以它会给我一个= [2]的结果。

我能够弄清楚如何过滤重复项，现在我将如何摆脱重复项？

不需要直接回答，只需要一点提示或提示：）

我能够在stackoverflow上找到它。它做我想要的，但我不明白代码，有人可以为我分解吗？

d = {}
for i in l: d[i] = d.has_key(i)

[k for k in d.keys() if not d[k]]

Answer 1

>>> a = [1, 5, 2, 5, 1]
>>> from collections import Counter
>>> [k for k, c in Counter(a).iteritems() if c == 1]
[2]

Answer 2

听到您的代码所做的事情：

d = {}
for i in list:
    # if the item is already in the dictionary then map it to True,
    # otherwise map it to False 
    # the first time a given item is seen it will be assigned False,
    # the next time True
    d[i] = d.has_key(i)

# pull out all the keys in the dictionary that are equal to False
# these are items in the original list that were only seen once in the loop
[k for k in d.keys() if not d[k]]

过滤列表，只有唯一值 - 使用python

2 个答案: