我的Access(2003)数据库中有一个备忘录字段,用于存储Outlook中文件夹的EntryID(大约750个字符)。我正在尝试取回 string 以使用以下代码将一些邮件移动到该文件夹ID:
Dim myNameSpace As Outlook.NameSpace
Dim StoreID As String
Dim target as String 'This is the long EntryID string
Dim objMail as mailitem 'some mail
Set myNameSpace = Application.GetNamespace("MAPI")
StoreID = Application.GetNamespace("MAPI").folders("LiveLink").StoreID
Set dossier = myNameSpace.GetFolderFromID(target, StoreID)
objMail.Move dossier
在这种情况下,target
var只有前252个字符而不是748个字符。有趣的是,如果没有其他文件夹具有相同的~255个第一个字符,Outlook仍将找到正确的文件夹。但在某些情况下,它会崩溃,因为它不止一个。我正在使用 Recordset 从数据库中获取备忘录。这是我的SQL:
SELECT EntryID FROM Folder
我终于找到了一些关于这种行为的信息:http://allenbrowne.com/ser-63.html。但是,我没有在我的查询中使用任何联合或任何特殊内容,因为你可以看到......
为什么它仍然被截断?
数据库中的原始备忘录/字符串:
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
SQL查询后截断的memo / object / field / string:
00000000CE5B922DF5D7654C993FFDB4FF79A7A00100000057010000307E7E2D317E305C307E4C6976656C696E6B204851457E307E2D315C307E4C6976656C696E6B204851457E2D357E305C307E4C6976656C696E6B204851457E313233373235387E2D355C307E4C6976656C696E6B204851457E3130323336333431
答案 0 :(得分:1)
如您的链接所示,这应该有效
Set rs = CurrentDb.Execute("SELECT Mid(EntryID, 1,250) AS part1, " & _
" Mid(EntryID,251,250) AS part2," & _
" Mid(EntryID,501,250) AS part3," & _
" Mid(EntryID,751,250) AS part4," & _
" Mid(EntryID,1001,250) AS part5 " & _
" FROM Folder;")
target = rs("part1") & rs("part2") & rs("part3") & rs("part4") & rs("part5")
答案 1 :(得分:0)
我已经实现了这个c#代码:
private string GetMemoField(string TableName, string FieldName, string IdentityFieldName, string IdentityFieldValue, OleDbConnection conn)
{
string ret = "";
OleDbCommand cmd1 = new OleDbCommand("SELECT " + FieldName + " FROM “ + TableName + “ WHERE " + IdentityFieldName + "=" + IdentityFieldValue, conn);
var reader = cmd1.ExecuteReader(System.Data.CommandBehavior.SequentialAccess); // Create the DataReader that will get the memo field one buffer at a time
if (reader.Read())
{
long numberOfChars = reader.GetChars(/*Field pos*/ 0, 0, null, 0, 0); // Total number of memo field's chars
if (numberOfChars > 0)
{
int bufferSize = 1024;
char[] totalBuffer = new char[64*bufferSize]; // Array to hold memo field content
long dataIndex = 0;
do
{
char[] buffer = new char[bufferSize]; // Buffer to hold single read
long numberOfCharsReaded = reader.GetChars(0, dataIndex, buffer, 0, bufferSize);
if (numberOfCharsReaded == 0)
{
ret = new string(totalBuffer,0, (int)numberOfChars);
break;
}
Array.Copy(buffer, 0, totalBuffer, dataIndex, numberOfCharsReaded); // Add temporary buffer to main buffer
dataIndex += numberOfCharsReaded;
} while (true);
}
}
return ret;
}