Question

我有sql查询

SET @cumulative_sum := 0;
SELECT fct_sales.datDate, @cumulative_sum := @cumulative_sum + fct_sales.dblTotal AS     
cumulative_sum
FROM fct_sales
where
fct_sales.intProductID=40
and
fct_sales.datDate
between
'2011-01-01'
and
'2011-01-10'
 ORDER BY fct_sales.datDate ASC

哪个很好，并给我结果表

 _______________________________
 |     datDate|  Cumulative_sum|
 |____________|________________|          
 | 2011-01-02 |   5005         |
 |____________|________________|
 |2011-01-04  |   7007         |
 |____________|________________|

然而，我要求的是：

  _____________________________
 |     datDate|  Cumulative_sum|
 |____________|________________| 
 |  2011-01-01|  5005          |
 |____________|________________| 
 |  2011-01-02|  5005          |
 |____________|________________| 
 |  2011-01-03|  5005          |
 |____________|________________| 
 |  2011-01-04|  7007          |
 |____________|________________| 
 |  2011-01-05|  7007          |
 |____________|________________| 
 |  2011-01-06|  7007          |
 |____________|________________| 
 |  2011-01-07|  7007          |
 |____________|________________| 
 |  2011-01-08|  7007          |
 |____________|________________| 
 |  2011-01-09|  7007          |
 |____________|________________| 
 |  2011-01-10|  7007          |
 |____________|________________|

我该如何做到这一点？

Answer 1

由于您的数据不适合解决您的问题.. 但无论你提供什么，我认为这会对你有帮助..

SELECT datDate, Cumulative_sum from fct_sales where Cumulative_sum > 5005 AND Cumulative_sum < 7007 AND intProductID = '40' ORDER BY datDate ASC

Answer 2

试试这个

SELECT datDate, Cumulative_sum FROM fct_sales WHERE intProductID='40' AND datDate BETWEEN '2011-01-01' AND '2011-01-10' GROUP BY datDate

Answer 3

您好基本上对于此查询，您需要3件事：

日期集
使用相同的表加入fct_sales以获取nextDate
制作一组日期并加入fct_sales。

如果你想要5005总和将在2011-01-01日期我认为这是不可能的，因为如果列表中有超过2个Cumulative_sums，它们会相互重叠......

示例并不漂亮，因为您需要日期范围。有时在db中有时间表，这将有助于减少查询代码。如果这对你没有帮助，那么至少会有一点用处：）

<强> SQLFIDDLE

所以这是我的例子：

 SELECT
    a.Date
    ,b.Cumulative_sum
    FROM
      (SELECT DATE_FORMAT(curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY, '%Y-%m-%d') AS Date
       FROM
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS a CROSS
       JOIN
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS b CROSS
       JOIN
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS c) a,
       (SELECT 
        fc1.datDate, 
        fc1.Cumulative_sum, 
         (SELECT MIN(fc2.datDate)  
          from fc fc2 
          WHERE fc1.datDate < fc2.datDate ) AS nextDate
    from fc fc1) b
      where (a.Date between '2011-01-01' and '2011-01-10')
        AND a.Date>=b.datDate 
        AND a.Date < COALESCE(b.nextDate, '2011-01-11')
      ORDER BY a.Date, b.Cumulative_sum

结果：

DATE    CUMULATIVE_SUM
2011-01-02  5005
2011-01-03  5005
2011-01-04  7007
2011-01-05  7007
2011-01-06  7007
2011-01-07  7007
2011-01-08  7007
2011-01-09  7007
2011-01-10  7007

使用查询数据查询示例：

SET @cumulative_sum := 0;
SELECT
    a.Date
    ,b.Cumulative_sum
    FROM
      (SELECT DATE_FORMAT(curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY, '%Y-%m-%d') AS Date
       FROM
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS a CROSS
       JOIN
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS b CROSS
       JOIN
         (SELECT 0 AS a
          UNION ALL SELECT 1
          UNION ALL SELECT 2
          UNION ALL SELECT 3
          UNION ALL SELECT 4
          UNION ALL SELECT 5
          UNION ALL SELECT 6
          UNION ALL SELECT 7
          UNION ALL SELECT 8
          UNION ALL SELECT 9) AS c) a,
       (SELECT
    fc1.datDate,
    fc1.Cumulative_sum,
         (SELECT MIN(fc2.datDate) AS datDate
            FROM (SELECT fct_sales.datDate, @cumulative_sum := @cumulative_sum + fct_sales.dblTotal AS     
                    cumulative_sum
                  FROM fct_sales
                 where
                fct_sales.intProductID=40
                and fct_sales.datDate between '2011-01-01' and '2011-01-10') fc2
          WHERE fc1.datDate < fc2.datDate ) AS nextDate
        FROM (SELECT fct_sales.datDate, @cumulative_sum := @cumulative_sum + fct_sales.dblTotal AS     
              cumulative_sum
             FROM fct_sales
             where
             fct_sales.intProductID=40
            and fct_sales.datDate between '2011-01-01' and '2011-01-10' ) fc1) b
      where (a.Date between '2011-01-01' and '2011-01-10')
        AND a.Date>=b.datDate 
        AND a.Date < COALESCE(b.nextDate, '2011-01-11')
      ORDER BY a.Date, b.Cumulative_sum

在mysql中显示相同数据的行

3 个答案: