Question

H，之前我把我的脚本搞砸了。然后我的整个剧本变得疯狂。现在，我删除了与分页相关的所有脚本，突然间，现在我无法显示所有相同ID的行。例如。对于id 99，我在sql中有9行相同的id。但它只显示5行。请帮忙谢谢。

  $query="SELECT ua.* FROM useradvert ua INNER JOIN users u ON  ua.id =u.id
     WHERE ua.id='".$id."'";



$stmt = $conn->prepare($query); 
$stmt->execute();
$res2 = $stmt->get_result(); 
$row2 = $res2->fetch_array();


$_SESSION['name2'] = $row2['name2'];
$_SESSION['color2'] = $row2['color2'];
$_SESSION['hobby2'] = $row2['hobby2'];
$_SESSION['radiobtn'] = $row2['radiobtn'];
$_SESSION['kupon'] = $row2['kupon'];
$_SESSION['image'] = $row2['image'];
$_SESSION['image2'] = $row2['image2'];

继续下面......同一页

while ($row2 = $res2->fetch_array(MYSQLI_ASSOC)){

echo "<li>".$_SESSION['name2'] = $row2['name2']."</li>";
    echo "<li>".$_SESSION['color2'] = $row2['color2']."</li>";
    echo "<li>".$_SESSION['hobby2'] = $row2['hobby2']."</li>";
    echo "<li>".$_SESSION['radiobtn'] = $row2['radiobtn']."</li>";
    echo "<li>".$_SESSION['kupon'] = $row2['kupon']."</li>";
    echo  "<li>".$_SESSION['image'] = $row2['image']."</li>";
    echo "<li>".$_SESSION['image2'] = $row2['image2']."</li>";}

Answer 1

你应该删除这段代码，用fetch_array（）函数正确循环：

$row2 = $res2->fetch_array(); 
$_SESSION['name2'] = $row2['name2']; 
$_SESSION['color2'] = $row2['color2']; 
$_SESSION['hobby2'] = $row2['hobby2'];
$_SESSION['radiobtn'] = $row2['radiobtn']; 
$_SESSION['kupon'] = $row2['kupon']; 
$_SESSION['image'] = $row2['image']; 
$_SESSION['image2'] = $row2['image2'];

Answer 2

看起来您的SQL查询可能导致问题，请尝试删除双引号

$ query =＆＃34; SELECT ua。* FROM useradvert ua INNER JOIN users u ON ua.id = u.id WHERE ua.id =＆＃39;＆＃34;。$ id。＆＃34;＆＃39;＆＃34;;

要

$ query =＆＃34; SELECT ua。* FROM useradvert ua INNER JOIN users u ON ua.id = u.id WHERE ua.id =＆＃39;。$ id。＆＃39;＆＃34;;

无法显示相同ID的所有行 - PHP

2 个答案: