Question

我有3个XML文件，如下所示，我想将所有这3个文档连接在一起，以便我可以执行聚合功能，以了解特定分类名称的销售量。但是看起来我编写的代码有问题。请指导我如何在三个文件上执行聚合功能。

ClassDescription.XML
<classification name="Electronic">
   <Description>electronic devices that requires electric</Description>
</classification>
<classification name="SoftToy">
   <Description>Fluffy toys that kids like</Description>
</classification>


ToyClassification.XML
<toy toyID="11">
  <name>Doll</name>
  <classification>SoftToy</classification>
</toy>
<toy toyID="22">
  <name>Xbox</name>
  <classification>Electronic</classification>
</toy>
<toy toyID="33">
  <name>PS3</name>
  <classification>Electronic</classification>
</toy>


 ToySale.XML
 <toySale companyID="1" toyID="11" >
   <amount>15</amount>
 </toySale>
 <toySale companyID="3" toyID="11" >
   <amount>12</amount>
 </toySale>
 <toySale companyID="1" toyID="22" >
   <amount>3</amount>
 </toySale>
 <toySale companyID="2" toyID="33" >
   <amount>7</amount>
 </toySale>



<ClassList>
  <classification name="SoftToy">
    <totalSale>4</totalSale>
  </classification>
  <classification name="Electronic">
    <totalSale>3</totalSale>
  </classification>
</ClassList>

下面是我的代码，但似乎无法正常工作。我知道这个工作的正确xquery是什么？

for $class in (ClassDescription.XML)//classification/@name
for $toyClass in (ToyClassification.XML)//toy/@toyID
for $sale in (ToySale.XML)//toySale/@toyID
let $sum := (ToySale.XML)//toySale[@toyID = $toyClass]
where $sale=$toyClass and $class=$toyClass/../name
order by sum($sum/amount)
return <ClassList>{$class}</ClassList>

Answer 1

此查询：

for $total-sale in
    let $vClasses := doc('file:///c:/temp/delete/classDescription.xml'),
        $vDetails := doc('file:///c:/temp/delete/toyClassification.xml'),
        $vSales   := doc('file:///c:/temp/delete/toySale.xml')
     return
       for $c in $vClasses/*/*
        return
           let $d := $vDetails/*/*[classification eq $c/@name],
               $s := $vSales/*/*[@toyID = $d/@toyID]
             return
                <classification name="{$c/@name}">
                         <totalSale>{sum($s/amount)}</totalSale>
                </classification>
  order by $total-sale/totalSale descending
  return $total-sale

当三个XML文档驻留在相应的文件中：

C：/temp/delete/classDescription.xml：

<t>
    <classification name="Electronic">
        <Description>electronic devices that requires electric</Description>
    </classification>
    <classification name="SoftToy">
        <Description>Fluffy toys that kids like</Description>
    </classification>
</t>

C：/temp/delete/toyClassification.xml：

<t>
    <toy toyID="11">
        <name>Doll</name>
        <classification>SoftToy</classification>
    </toy>
    <toy toyID="22">
        <name>Xbox</name>
        <classification>Electronic</classification>
    </toy>
    <toy toyID="33">
        <name>PS3</name>
        <classification>Electronic</classification>
    </toy>
</t>

C：/temp/delete/toySale.xml：

<t>
    <toySale companyID="1" toyID="11" >
        <amount>15</amount>
    </toySale>
    <toySale companyID="3" toyID="11" >
        <amount>12</amount>
    </toySale>
    <toySale companyID="1" toyID="22" >
        <amount>3</amount>
    </toySale>
    <toySale companyID="2" toyID="33" >
        <amount>7</amount>
    </toySale>
</t>

会产生想要的正确结果：

<classification name="SoftToy">
   <totalSale>27</totalSale>
</classification>
<classification name="Electronic">
   <totalSale>10</totalSale>
</classification>

请注意，在其他两个表中根本不使用CompanyID数据。

分组和聚合

1 个答案: