返回列表中以给定的最小频率发生的项目

Question

需要帮助创建函数freqitems（S，p），它返回序列S中以至少p％频率出现的项目的排序列表，没有重复项。示例输出应该是这样的：

>>> freqitems([2,2,2,3],50)
[2]
>>> freqitems(5*["alpha"]+["beta"]+3*["gamma"]+7*["delta"], 25)
['alpha', 'delta']
>>> freqitems(5*["alpha"]+["beta"]+3*["gamma"]+7*["delta"], 33)
['delta']

Answer 1

yourlist = 5*["alpha"]+["beta"]+3*["gamma"]+7*["delta"]

def freqitems(sequence, p):
  import collections
  counter = collections.Counter(sequence)
  return sorted([k for k,v in counter.iteritems() if 100.*v/len(sequence) >= p])

print freqitems(yourlist, 25)
print freqitems(yourlist, 33)