Question

我需要模拟Method1来测试我的进程异常。我怎么能这样做？

public interface IFoo
{
    void Method1();
    object Method2();
}
public class Foo : IFoo
{
    public void Method1()
    {
        // Do something
    }

    public object Method2()
    {
        try
        {
            // Do something
            Method1();
            // Do somenthing

            return new object();
        }
        catch (Exception ex)
        {
            // Process ex
            return null;
        }
    }
}

Answer 1

fooMock =  MockRepository.GenerateStub<IFoo>();
fooMock.Stub(x => x.Method1()).Return("Whatever");

Answer 2

界面是红鲱鱼。您必须模拟实现Foo并将Method1更改为虚拟：

...
public virtual void Method1()
...

使用throw扩展来创建您想要处理的异常：

var fooMock = MockRepository.GenerateStub<Foo>();
fooMock.Expect(foo => foo.Method1()).Throw(new Exception());

var actual = fooMock.Method2();
Assert.IsNull(actual);

fooMock.VerifyAllExpectations();

如何模拟一个方法？

2 个答案: