我目前正在编写表达式评估程序,并遇到了有关多态性的问题。 我的类层次结构如下:Divide继承自继承自基类Expression的Operator。当我用基类Expression实例化一个Divide类型的Object并尝试访问函数divide(int,int)时,我得到以下错误:
“Expression.cpp:在成员函数中'int Expression :: evaluate()': Expression.cpp:37:6:错误:'class Expression'没有名为'divide'的成员“
这是“Expression.h”
#ifndef EXPRESSION_H
#define EXPRESSION_H
#include <string>
using namespace std;
class Operator;
class Divide;
class Expression
{
protected:
char **ana, *exp;
public:
Expression();
~Expression();
Expression(char* ex);
int evaluate();
void tokenize();
class EmptyException
{
public:
EmptyException(string a){reason = a;};
string getReason() const{return reason;};
private:
string reason;
};
};
#endif
这是“Expression.cpp”
#include "Expression.h"
#include "Stack.h"
#include "Queue.h"
#include "Node.h"
#include <iostream>
#include <cstring>
#include <stdio.h>
#include <ctype.h>
#include "Operator.h"
#include "Divide.h"
Expression::Expression()
{
}
Expression::~Expression()
{
delete [] exp;
}
Expression::Expression(char* ex)
{
exp = ex;
//tokenize();
}
int Expression::evaluate()
{
Stack stack;
Expression *tmp;
Divide d;
tmp = &d;
tmp->divide(4, 2);
stack.push(tmp);
tmp = stack.pop();
}
void Expression::tokenize()
{
int space = 0;
for(int i =0 ; i < strlen(exp); i++)
{
if(exp[i] == ' ')
space++;
}
char ** ana = new char*[space + 1];
ana[0] = strtok(exp, " ");
for(int i = 1 ; i < space + 1; i++)
{
ana[i]= strtok (NULL, " ");
}
}
现在是“operator.h”
#ifndef OPERATOR_H
#define OPERATOR_H
#include "Expression.h"
using namespace std;
class Operator : public Expression
{
protected:
bool unary, binary;
public:
Operator();
bool isUnary() const;
bool isBinary() const;
};
#endif
“Operator.cpp”
#include "Operator.h"
#include <string>
#include <cmath>
#include "Expression.h"
Operator::Operator()
{
}
bool Operator::isUnary() const
{
if(unary)
return true;
else
return false;
}
bool Operator::isBinary() const
{
if(binary)
return true;
else
return false;
}
“Divide.h”
#ifndef DIVIDE_H
#define DIVIDE_H
#include <string>
#include "Operator.h"
class Expression;
using namespace std;
class Divide : public Operator
{
private:
char id;
public:
Divide();
Divide(char);
int divide(int a, int b);
char identity() const;
};
#endif
“Divide.cpp”
#include "Divide.h"
int Divide::divide(int a, int b)
{
return a/b;
}
Divide::Divide(char _id)
{
id = _id;
}
char Divide::identity() const
{
return id;
}
以及make文件
main: Expression.o Equation.o Operator.o Divide.o Stack.o Queue.o main.o
g++ -static main.o Equation.o Expression.o Operator.o Divide.o Stack.o Queue.o -o main
main.o : main.cpp
g++ -c main.cpp
Equation.o : Equation.cpp Equation.h
g++ -c Equation.cpp
Expression.o : Expression.cpp Expression.h
g++ -c Expression.cpp
Operator.o : Operator.cpp Operator.h Expression.h
g++ -c Operator.cpp
Divide.o : Divide.cpp Divide.h Operator.h
g++ -c Divide.cpp
Stack.o : Stack.cpp Stack.h Node.h
g++ -c Stack.cpp
Queue.o : Queue.cpp Queue.h Node.h
g++ -c Queue.cpp
我遗漏了所有其他运营商,例如。另外,减去等因为它们都与Divide相同,并且会使这个问题更加复杂化。
答案 0 :(得分:4)
很清楚,对吗? Expression
没有方法divide
。
Expression *tmp;
Divide d;
tmp = &d;
tmp->divide(4, 2); //tmp is an Expression*
另外...... 你为什么要这样做?有什么问题:
Divide d;
d.divide(4,2);
答案 1 :(得分:1)
您的问题是,您在名为divide
的变量上调用了temp
,这是指向Expression
的指针:tmp->divide(4, 2);
您应该在{{1}上调用divide 1}}变量。