Question

我运行此代码并从Valgrind获取此消息，我是c ++和Linux的新手，但我知道我必须修复它。请问你能告诉我什么是错的吗？我正在使用Ubuntu。

信息如下：

==29304== Thread 1:
==29304== 72 bytes in 18 blocks are definitely lost in loss record 55 of 89
==29304==    at 0x402641D: operator new(unsigned int) (vg_replace_malloc.c:255)
==29304==    by 0x4032BBC: GmpPipePlayer::GmpPipePlayer(IOBase*, Referee*, unsigned char, int, DataBoard const*, int, char const*, int) (unixgmppipe.cpp:126)
==29304==    by 0x40329F9: GmpPipePlayer::CreateFunc(IOBase*, Referee*, unsigned char, int, DataBoard const*, void*) (unixgmppipe.cpp:55)

代码是： int down [2]，up [2];

pipe(down);   
pipe(up);

_pid = fork();

if (_pid < 0)
    exit(1);


if (_pid == 0)
{
    close(down[1]);
    close(up[0]);

    dup2(down[0], 0);
    dup2(up[1], 1);

    execl("/bin/sh", "sh", "-c", cmd_line, NULL);

    _exit(1);
}

close(down[0]);
close(up[1]);
_down = down[1];
_up = up[0];

_reader_thd = new Thread(reader_wrapper, this); //here is the error happening.

函数readre_wrapper是：

THREAD_Return GmpPipePlayer::reader_wrapper(void *p)

{
    GmpPipePlayer *t = (GmpPipePlayer *)p;

    t->reader_fn();

    return NULL;
}

这个新线程被多次调用。在我再次打电话之前，我会做以下事情：

if (_pid > 0)
{
    kill(_pid, SIGTERM);
    _pid = 0;
}

if (_up)
{
    close(_up);
    _up = 0;
}

if (_down)
{
    close(_down);
    _down = 0;
}

任何想法有什么不对？

Answer 1

好吧，你的new永远不会被delete匹配。您的代码中的某个位置需要delete _reader_thd;。或者根本不使用动态对象。

valgrind：在新的线程中，块绝对会在损失记录中丢失

1 个答案: