Question

我有三种模式：

class Model_1(models.Model):
    ...

class Model_2(models.Model):
    m1 = models.ManyToManyField(Model_1,...
    ...

class Model_3(models.Model):
    m2 = models.ManyToManyField(Model_2,...
    ...

我得到了Model_1的对象：

object = Model_1.objects.get(id=my_id)

如何从对象获取相关的Model_3？

Answer 1

如果您对2个查询没问题，

m2_objects = objects.model_2_set.all()
m3_objects = Model_3.objects.filter(m2__in=m2_objects)

Answer 2

ManyToMany为您提供一个不是一个对象的集合。你可以像这样获得Model_3的对象

>>> object = Model_1.objects.get(id=my_id)
>>> for o2 in object.model_2_set.all():
>>>     for o3 in o2.model_3_set.all():
>>>         print o3  # o3 is one of Model_3 object

将model_2_set更改为您提供的related_name。

Answer 3

这是一个prefetch_related只能执行3次查询的解决方案。

object = Model_1.objects.get(id=my_id) # 1 query
m2_set = object.model2_set.prefetch_related('model3_set') # 2 queries for model 2 and 3
for o3 in chain(*(m2.m3_set.all() for m2 in m2_set)): # chaning o3 sets (no query)
    print o3 # probably no query

源： prefetch_related：https://docs.djangoproject.com/en/dev/ref/models/querysets/#prefetch-related 链：http://docs.python.org/release/2.6.5/library/itertools.html#itertools.chain

Answer 4

Model_3.objects.filter(m2__m1=object)

这不直观，但如果值在相关对象集合中，则__exact过滤器匹配。

编辑：这是shell输出，用于踢。

>>> from myapp.models import *
>>> m1 = Model_1.objects.create(name='it')
>>> m2 = Model_2.objects.create()
>>> m3 = Model_3.objects.create()
>>> 
>>> m1.model_2_set.add(m2)
>>> m2.model_3_set.add(m3)
>>> Model_3.objects.filter(m2__m1=m1).count()
1

如何获得相关对象？

4 个答案: