Question

我确信这已经被问过，并且之前已经回答过，但要么我是愚蠢的，要么就是没有一个答案适合我。也许我只是不理解它。但是，这是问题所在;我上了这堂课：

import sqlite3

class User:
   def __init__(self, name, age):
        self.name = name
        self.age = age



   def saveToDatabase(self):
        connection = sqlite3.connect("users.db")
        cur = connection.cursor()

        cur.execute("DROP TABLE IF EXISTS users")
        cur.execute("CREATE TABLE users (name TEXT PRIMARY KEY, age INTEGER)")
        cur.execute("INSERT OR REPLACE INTO users VALUES (?,?)", (self.name, self.age))

        connection.commit()
        connection.close()

    @staticmethod
    def printUserFromDatabase(name):
        connection = sqlite3.connect("users.db")
        cur = connection.cursor()

        cur.execute("SELECT * FROM users WHERE name=?", name)
        print(cur.fetchone())

        connection.close()

它有效，数据库被创建，我可以添加用户，但是当我尝试从数据库打印用户时，会发生这种情况：

>>> tom = User("Tom", 24)
>>> tom.saveToDatabase()
>>> User.printUserFromDatabase("Tom")
Traceback (most recent call last):
  File "<pyshell#7>", line 1, in <module>
    User.printUserFromDatabase("Tom")
  File "C:\Users\Markus\Desktop\foo\foo.py", line 25, in printUserFromDatabase
    cur.execute("SELECT * FROM users WHERE name=?", name)
sqlite3.ProgrammingError: Incorrect number of bindings supplied. The current statement uses 1, and there are 3 supplied.
>>>

Answer 1

因为名称是可迭代的，所以它会尝试将其解压缩...将其放入一个仅用于修复的元组中

cur.execute("SELECT * FROM users WHERE name=?", (name,))

关于提供的绑定数量的Python sqlite3错误

1 个答案: