Question

while((player1chip==-1)||(player2chip==-1)||(player3chip==-1)){                                                              
    player1chip=-1; player2chip=-1; player3chip=-1;                                                       
    printf("How many chips would you like to play with (3-10):\n");
    scanf("%d%d%d", &player1chip, &player2chip, &player3chip);
    getchar();
}

我希望一次获得3个值，但循环似乎已运行3次... 我该怎么办？

Answer 1

int p1chip=-1, p2chip=-1, p3chip=-1;
do {
  printf("How many chips would you like to play with (3-10)?\n");
  scanf("%d%d%d", &p1chip, &p2chip, &p3chip);
} while ((p1chip == -1) || (p2chip == -1) || (p3chip == -1))

试试。

Answer 2

scanf（）语句对于您尝试执行的操作有点奇怪，因为您说通过使用“％d％d％d”预期三个数字没有分离。如果while循环的目的是填充playerchip变量，你应该为它们使用一个数组并迭代数组，如下所示：

playerchip[3];   
for(int i=0; i<3; i++) {
    printf("How many chips would player %d like to play with (3-10)?:\n", i);
    scanf("%d", &playerchip[i]);
}

如果保留命名方案，则无法使用循环轻松填充变量。要回答你的原始问题，要一次获取多个数字，你需要在scanf（）语句中有一些分隔符：

scanf("%d %d %d", &a, &b, &c);

这样每个人都知道一个号码何时结束而另一个号码何时开始。

如何在while循环中扫描多个输入？

2 个答案: