大家好,我已经开始使用gprof进行分析工作了,除了-f选项允许我指定在调用图中查看特定函数之外,它工作正常。
例如
Call graph (explanation follows)
granularity: each sample hit covers 4 byte(s) no time propagated
index % time self children called name
0.00 0.00 1/1 __do_global_ctors_aux [13]
[5] 0.0 0.00 0.00 1 global constructors keyed to main [5]
0.00 0.00 1/1 __static_initialization_and_destruction_0(int, int) [6]
-----------------------------------------------
0.00 0.00 1/1 global constructors keyed to main [5]
[6] 0.0 0.00 0.00 1 __static_initialization_and_destruction_0(int, int) [6]
-----------------------------------------------
0.00 0.00 1/1 main [4]
[7] 0.0 0.00 0.00 1 car::DisplayPrice() [7]
-----------------------------------------------
0.00 0.00 1/1 main [4]
[8] 0.0 0.00 0.00 1 car::showc() [8]
-----------------------------------------------
0.00 0.00 1/1 main [4]
[9] 0.0 0.00 0.00 1 car::car(std::string, int) [9]
0.00 0.00 1/1 vehical::vehical(int, int) [12]
-----------------------------------------------
0.00 0.00 1/1 main [4]
[10] 0.0 0.00 0.00 1 car::~car() [10]
-----------------------------------------------
0.00 0.00 1/1 main [4]
[11] 0.0 0.00 0.00 1 vehical::show() [11]
-----------------------------------------------
0.00 0.00 1/1 car::car(std::string, int) [9]
[12] 0.0 0.00 0.00 1 vehical::vehical(int, int) [12]
-----------------------------------------------
现在,如果我指定
gprof -f car::car(std::string, int) a.out gmon.out
我收到错误
意外令牌附近的语法错误'('
现在,如果我这样做
gprof -f car :: car(std :: string,int)a.out gmon.out
我收到错误
没有这样的文件或目录
如果我尝试将函数放在双引号中,我得到如上所述的输出而没有变化..
CAN有人请帮帮我吗? 提前致谢
答案 0 :(得分:3)
()取自你的shell。试试这样:
gprof -f 'car::car(std::string, int)' a.out gmon.out