Question

假设我有下一张表

Table names
id | name
1  | mike
2  | john
3  | jack

Table attributes
name_id | skill
1 | css
1 | html
1 | php
2 | html
2 | java
2 | css
3 | java

我需要获取所有id和名称，例如css和html属性。我尝试使用“JOIN”但搜索的属性数量可能不同。

我还没有尝试过任何其他因为我无法弄清楚要尝试什么。

谢谢

Answer 1

尝试使用GROUP BY ...和HAVING COUNT(DISTINCT ...)：

SELECT name_id
FROM attributes
WHERE skill IN ('css', 'html')
GROUP BY name_id
HAVING COUNT(DISTINCT skill) = 2

查看在线工作：sqlfiddle

您也可以加入以获取姓名。

Answer 2

select names.id, names.name
from
    names
        inner join 
    attributes
        on names.id = attributes.name_id
where skill in ('css','html')
group by names.id, names.name
having count(distinct skill) = 2 -- where 2 is the number of skills you are looking for

MySQL：获取具有不同参数的行

2 个答案: