Question

我有下表

var A = ["Soup", "Juice", "Tea", "Others"];
var B = ["Soup", "Juice", "Water", "Others"];
var C = ["Soup", "Juice", "Coffee", "Tea", "Others"];
var select = document.getElementById('category').options.length;

    for (var i = 0; i < select; ) {
        document.getElementById('category').options.remove(i);
    }

if (document.getElementById("meal").value == "A") {


    for (var i = 0; i < A.length; i++) {
        var newSelect = document.createElement('option');
        selectHTML = "<option value='" + A[i] + "'>" + A[i] + "</option>";
        newSelect.innerHTML = selectHTML;
        document.getElementById('category').add(newSelect);
    }
}

else if (document.getElementById("meal").value == "B") {

    for (var i = 0; i < B.length; i++) {
        var newSelect = document.createElement('option');
        selectHTML = "<option value='" + B[i] + "'>" + B[i] + "</option>";
        newSelect.innerHTML = selectHTML;
        document.getElementById('category').add(newSelect);
    }
}

else if (document.getElementById("project").value == "C") {

    for (var i = 0; i < C.length; i++) { 
        var newSelect = document.createElement('option');
        selectHTML = "<option value='" + C[i] + "'>" + C[i] + "</option>";
        newSelect.innerHTML = selectHTML;
        document.getElementById('category').add(newSelect);
    }
}

如何获取stage_id = 1且is_completed = 1且stage_id = 2且is_completed = 0

的所有task_ids

Answer 1

您可以使用AND和OR的组合，例如：

SELECT task_id
FROM tasks
WHERE (stage_id = 1 AND is_completed = 1)
OR (stage_id = 2 AND is_completed = 2)
GROUP BY task_id;

Answer 2

使用union：

select task_id from table where stage_id = 1 and is_completed = 1
union
select task_id from table where stage_id = 2 and is_completed = 0

Answer 3

来自mt_task_status的SELECT * 哪里 task_id in（SELECT task_id FROM mt_task_status WHERE stage_id ='1'和is_completed ='1'）和task_id in（SELECT task_id FROM mt_task_status WHERE stage_id ='2'和is_completed ='0'）和（1,2）中的stage_id 按task_id排序

获取具有相同主键的行，在参考表中具有不同的状态

3 个答案: